4. When peforming multiple trials at different temperatures, a student obtained the following trendline equation. Calculte AH and AS. y 1737x18.31
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- What is ΔHsys for a reaction at 16.9 °C with ΔSsurr = -159 J mol-1 K-1 ? Express your answer in kJ mol-1 to at least two significant figures. (Please type answer no write by hend)Ethyl heptanoate (EH), a food aroma compound, was added to water and allowed to come to equilibrium with a known volume of air and results showed that its partition coefficient, [EHair]/[EHwater] is equal to 1.8 x 10-2. In the same experiment with oil in place of water, its partition coefficient, [EHair]/[EHoil] is found to be lower at 6.0 x 10-6. Account for the difference between the two values.By the use of Henderson Hasselbalch equation; pH = pKa + log{[acetate ion]/[acetic acid]} 4.5 = 4.75 + log{[0.10 M]/[acetic acid]} -0.25 = log{[0.10 M]/[acetic acid]} [Acetic acid] = 0.10 M/ 10-0.25 [Acetic acid] = 0.10 M/0.56 [Acetic acid] = 0.1786 M Moles of sodium acetate dissolved in 250 mL buffer solution = 0.10 M× (250mL/1000mL) × 1L = 0.025 mol Weight (w) of sodium acetate (purity 100%) dissolved to prepare 250 mL of solution with buffer concentration of 0.10 M is calculate as follow; w100% = 0.025 mol × 82.0343 g/mol = 2.051 g Weight (w) of sodium acetate (purity 99%) is calculate as follow; w99% = 2.051 g× (100/99) = 2.072 g What was the volume of 6.12 M acetic acid HC2H3O2 needed to prepare the 250 mL acetic acid/acetate ion buffer solution required in this part? Show your calculations.
- Solute S has a partition co-efficient of 3.0 between water (Phase 1) and Chloroform (Phase 2). (a) Calculate the concentration of S in chloroform if [S(aq)] is 0.015 M. (b) If the volume of water is 75.0 mL and the volume of chloroform is 15.0 mL, find the quotient (mol S in chloroform)/(mol S in water).I need the theoretical molar extinction coefficient of paranitrophenol in mol^-1cm^-1 (using moles not μM). I have to calculate the % difference.At the experimental level it was 7,200 mol^-1cm^-1In the synthesis of hydrocarbons, the carbon source is carbon dioxide. Although the CO2 concentra?on in the atmosphere raises at a drama?c speed, point sources are probably the easier sources for a PtX process. Iden?fy 3 possible point sources, explain why CO2 is formed and what challenges each of the three CO2 streams presents
- Use the following equilibria2CH4(g) <----> C2H6(g) + H2(g) Kc1 = 9.5 × 10-13CH4(g) + H2O(g) CH3OH(g) + H2(g) Kc2 = 2.8 × 10-21to calculate the value of Kc' for the following reaction:2CH3OH(g) + H2(g) <---> C2H6(g) + 2H2O(g) Enter your response in scientific notation, e.g. enter 2E3 for 2000What is the retardation factor of a pulse of dissolved benzene move through organic-rich wetland soil (organic carbon fraction of soil, foc=50%) if the effective porosity is 0.4 and the bulk density of the soil is 1.5 g/cm3. Follow these important hints: - Determine organic carbon partition coefficient (Koc) - Use this Equation: K oc = K d / f oc to calculate Kd. Select the range which includes your calculated answer. Group of answer choices 300 to 400 2.0 to 2.5 mg/l 2.0 to 2.5 2.6 to 4.8 0.5 to 1.0 2.6 to 4.8 mg/l None of these ranges include my answer.If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)
- Calculate delt g for Pbl2(s) + Pb2+(aq) +2I-(aq) T= 25C Kp= 8.7x10-9Assume no acid-base catalysis occurs and the following data: Under biological conditions (310 K) 1. dGb = -20.00 kJ/mol. 2. The dG of E +S binding to ES (dGs) is -3.00 kJ/mol. 3. dGd mismatch of energy in ES = +2.00 kJ/mol. What is the catalytic power (kcat/k_uncat) at 360 K? Use 1 decimal place.Is the product pure? how do you know? here is the results: Starting mass of benzyl 1.0883g Collected mass of product 0.8957g Product melting point 135˚C Mixture melting point (product mixed with benzoin) 114˚C Mixture melting point (product mixed with meso-hydrobenzoin) 135˚C