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4.35 L He/1 x 1 mole He/22.4 L He. When we solve this problem we get 0.19419642. Apply the significant figure rules to the final answer.   Then explain why the final answer makes sense using the example answer attached to help.

4.35 L He/1 x 1 mole He/22.4 L He. When we solve this problem we get 0.19419642. Apply the significant figure rules to the final answer.   Then explain why the final answer makes sense using the example answer attached to help.

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter2: Measurements And Calculations
Section: Chapter Questions
Problem 17ALQ: Complete the following and explain each in your own words: leading zeros are...
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4.35 L He/1 x 1 mole He/22.4 L He.

When we solve this problem we get 0.19419642. Apply the significant figure rules to the final answer.

 

Then explain why the final answer makes sense using the example answer attached to help.

01 ▶▶ 02 03 >> 04 >> 05 >> Significant Figure Rules Rules All nonzero digits are significant. Zeros that appear between other nonzero digits are always significant. Zeros that appear in front of all of the nonzero digits are called left-end zeros. Left-end zeros are never significant. Zeros that appear after all nonzero digits are called right-end zeros. Right-end zeros in a number that lacks a decimal point are not significant. Right-end zeros in a number with a decimal point are significant. This is true whether the zeros occur before or after the decimal point. 237 has three significant figures. 1.897 has four significant figures. 39,004 has five significant figures. 5.02 has three significant figures. 0.008 has one significant figure. 0.000416 has three significant figures. 140 has two significant figures. 75,210 has four significant Ligures. 620.0 has four significant figures. 19.000 has five significant figures. For multiplication and division problems, the answer should be rounded to the same number of significant figures as the measurement with the least number of significant figures.
Transcribed Image Text:01 ▶▶ 02 03 >> 04 >> 05 >> Significant Figure Rules Rules All nonzero digits are significant. Zeros that appear between other nonzero digits are always significant. Zeros that appear in front of all of the nonzero digits are called left-end zeros. Left-end zeros are never significant. Zeros that appear after all nonzero digits are called right-end zeros. Right-end zeros in a number that lacks a decimal point are not significant. Right-end zeros in a number with a decimal point are significant. This is true whether the zeros occur before or after the decimal point. 237 has three significant figures. 1.897 has four significant figures. 39,004 has five significant figures. 5.02 has three significant figures. 0.008 has one significant figure. 0.000416 has three significant figures. 140 has two significant figures. 75,210 has four significant Ligures. 620.0 has four significant figures. 19.000 has five significant figures. For multiplication and division problems, the answer should be rounded to the same number of significant figures as the measurement with the least number of significant figures.
Step 2: Calculate. 24 hr 1 d 1dx X 60 min 1 hr X 60 s 1 min 86, 400 s %D Applying the first conversion factor, the "d" unit cancels and 1 × 24 = 24. Applying the second conversion factor, the "hr" unit cancels and 24 × 60 = 1440. Applying the third conversion factor, the "min" unit cancels and 1440 × 60 = 86, 400. The unit that remains is "s" for seconds. Step 3: Think about your result. Seconds is a much smaller unit of time than days, so it makes sense that there are a very large number of seconds in one day.
Transcribed Image Text:Step 2: Calculate. 24 hr 1 d 1dx X 60 min 1 hr X 60 s 1 min 86, 400 s %D Applying the first conversion factor, the "d" unit cancels and 1 × 24 = 24. Applying the second conversion factor, the "hr" unit cancels and 24 × 60 = 1440. Applying the third conversion factor, the "min" unit cancels and 1440 × 60 = 86, 400. The unit that remains is "s" for seconds. Step 3: Think about your result. Seconds is a much smaller unit of time than days, so it makes sense that there are a very large number of seconds in one day.
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