4.6.32-GIAparcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 132 inches.(A) Find the dimensions of a rectangular box with square ends that satisfies the delivery service's restriction and has maximum volume. What is the maximum volume?(B) Find the dimensions (radius and height) of a cylindrical container that meets the delivery service's restriction and has maximum volume. What is the maximum volume?(A) The dimensions of the rectangular box arein.(Use a comma to separate answers as needed.)

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Asked Nov 18, 2019
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4.6.32-GI
Aparcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 132 inches.
(A) Find the dimensions of a rectangular box with square ends that satisfies the delivery service's restriction and has maximum volume. What is the maximum volume?
(B) Find the dimensions (radius and height) of a cylindrical container that meets the delivery service's restriction and has maximum volume. What is the maximum volume?
(A) The dimensions of the rectangular box arein.
(Use a comma to separate answers as needed.)
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4.6.32-GI Aparcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 132 inches. (A) Find the dimensions of a rectangular box with square ends that satisfies the delivery service's restriction and has maximum volume. What is the maximum volume? (B) Find the dimensions (radius and height) of a cylindrical container that meets the delivery service's restriction and has maximum volume. What is the maximum volume? (A) The dimensions of the rectangular box arein. (Use a comma to separate answers as needed.)

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Expert Answer

Step 1

Consider the given information:

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Length Girth s 132

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Step 2

Consider the fir...

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Since in this case we have a rectangular box with square ends, Suppose the side of the square = x Therefore, girth-4x length + girth 132 1+4x 132 I s132-4x Volume of the box (V) = /-x2 V = (132 -4x)x V = 132x2-4x dV 132x-12x For maximum volume = 0; 132x-12x20 X 11 Maximum volume(V 132x112 - 4x11 max -10648 in max

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Math

Calculus

Derivative