40 Spring A Spring B Spring C 2 30 --- 20 10 2 4 8 10 Deflection (mm) Problem 18.1 Spring Force (N)
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A: ∑MB = 0RA16- 40(12)- 5822 = 0 RA = 40 KN.∑Fy = 0RA+RB =…
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Q: I can't seem to understand how did 40kn came out on summation moment B, can you please explain.
A: Problem Explanation for step "summation of moment at B = 0"and calculation of RA
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Q: Answer only A and B. note: a = 4.5 m b = 33.0 kN/m c = 13 kN
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The force—deflection relationships for three springs are shown in the accompanying figure. What is the stiffness (spring constant) of each spring? Which one of the springs is the stiffest?
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- The given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. plate: fy = 241 mpa fu = 4141 mpa rivet: fv = 152 mpa a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivets8. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksih) what is the flexural rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)The answer are MAB = -42.9kft , MCB = 16.7 kft
- If the allowable bearing stress in the bolt is 18.855 ksi. what is the minimumrequired diameter of the bolt at B? b= .75” h= 7.874” Distances are in feet.5. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi e) what is the shear rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)6. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi f) what is the block shear rupture capacity of the shear plate of the shear connection in kips? (2 decimal places)
- Give an correct answer with proper method or i will give an dislike A cantilever beam of effective depth 315 mm has span of 2.5 m. The percentage of tensile reinforcement is 1.5% Fe-250 bars. Check the beam for its depth for deflection only. Take M20 conerete.17. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksiq) what is the tensile rupture capacity of flange plate of the flange connection in kips? (2 decimal places)13. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi m) what is the block shear rupture (L-shaped) capacity of flange plate of the flange connection in kips? (2 decimal places)
- c. Calculate "P" in KN considering failure on bearing on projected area. Two A36 16mm Thick Steel Plates Are Connected By Four Rivets With Fv=152 MPa As Shown. Given: Rivet Dia 20 mm x=100 mmA steel plate 375mm x 16mm thick is bolted by four bolts placed symmetrically to form a single lap joint. The bolts are spaced horizontally at a distance of 140mm and vertically at a distance of 150mm. If the diameter of bolt is 20 mm, calculate the design tensile strength in KN based on net section fracture considering a straight vertical path of failure Use Fy=248MPa and Fu=400MPa a) 1339.2 b) 1569.6 c)2092.8 d) 1488For a 28ft tall pin ended glue laminated 5 1/8 in x 12 column (A= 61.5 in2) braced at midheight in weak direction, determine critical buckling load, Pcr when Ix= 738in4, Iy= 134.6in4, E= 2100 Ksi