43 41-54 Find the absolute maximum and absolute minimumvalues of f on the given interval.41. f(x) = 12 + 4x − x², [0, 5]42. f(x) = 5 + 54x − 2x³, [0, 4]43. f(x) = 2x³ − 3x² − 12x + 1, [−2,3]44. f(x) = x³ − 6x² + 9x + 2, [−1,4]-45. f(x) = xª − 2x² + 3, [−2, 3]-46. f(x) = (x² --47. f(t) = t√√4-t²,t.48. f(x)1)³, [1,2][1,2]=2x² 4x² + 4², x218ر[-4, 4][-1,4]49. f(x) = xe50. f(x) = x - Inx,[¹,2]51. f(x) = ln(x² + x + 1), [−1, 1]52. f(x) = x − 2 tan ¹x, [0, 4]-53. f(t) = 2 cos t + sin 2t, [0, π/2]54. f(t) = t + cot (t/2), [π/4, 7π/4]

Answered: Image /qna-images/answer/039fa99e-a006-4e5d-88bd-c8e20a67a0bb.jpg

Answered: 43. f(x) = 2x³ - 3x² 12x + 1, [2, 3]

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter7: Distance And Approximation

Section7.1: Inner Product Spaces

Problem 15BEXP

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