-45 + 7(x + 2) - 6x (no justification needed) = -45+ (7x + 14) - 6x = -45+ (14 + 7x) - 6x = (-45 + 14) + 7x - 6x =-31 + 7x - 6x (no justification needed) = -31 + (7-6)x = -31 + 1x (no justification needed) = -31 + x = x + (-31)

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.4: The Addition-or-subtraction Method
Problem 21WE
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Explain each step, excluding those that are labeled as “no justification needed.” For each step, use a property of the real numbers and explain how the property is being applied.

 

This is for part 2 of the picture 

Task 2
Part 1
Part 2
Part 3
A = 6
B = 8
4
C = 3√675
15
23
21
D = 4√27
E = 3√7
11
5
-45 + 7(x + 2) — 6x (no justification needed)
= -45+ (7x + 14) - 6x
= -45+ (14 + 7x) - 6x
= (-45 + 14) + 7x - 6x
=-31 + 7x- 6x (no justification needed)
12
3
4√5
√16
27
= -31+ (7-6)x
= -31 + 1x (no justification needed)
= -31 + x
= x + (-31)
√28
-5.823
Transcribed Image Text:Task 2 Part 1 Part 2 Part 3 A = 6 B = 8 4 C = 3√675 15 23 21 D = 4√27 E = 3√7 11 5 -45 + 7(x + 2) — 6x (no justification needed) = -45+ (7x + 14) - 6x = -45+ (14 + 7x) - 6x = (-45 + 14) + 7x - 6x =-31 + 7x- 6x (no justification needed) 12 3 4√5 √16 27 = -31+ (7-6)x = -31 + 1x (no justification needed) = -31 + x = x + (-31) √28 -5.823
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