Question
Asked Sep 25, 2019
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You measure the electric field strength at points directly above the center of a square plate carrying charge uniformly over its surface. The data are given below. (x is the perpendicular distance above the plate.) Use the data to answer the following questions.
(a) Whatisthetotalchargeontheplate?
(b) Whatisthesizeoftheplate?
(c) There is something missing in these data. What is it?

下午4:55 9月25日週三
67%
doc-Os-7c-docs.googleusercontent.com
E (N/C)
x(cm)
0.01
5870
0.02
5860
1.2
4840
6.0
1960
12.0
754
221
24.0
48.0
57.6
26.7
72.0
96.0
16.2
8.45
120.0
240.0
2.34
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下午4:55 9月25日週三 67% doc-Os-7c-docs.googleusercontent.com E (N/C) x(cm) 0.01 5870 0.02 5860 1.2 4840 6.0 1960 12.0 754 221 24.0 48.0 57.6 26.7 72.0 96.0 16.2 8.45 120.0 240.0 2.34

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Expert Answer

Step 1

We can find the average of electric field as follows Eavg:

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5870 5860 4840 1960 754 221 57.6+26.7+16.1+8.45+2.34 Eas N/C 11 E 1783.29 N/C ag

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Step 2

We can find the average of distance from uniformly charged square plate (xavg) as follows:

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0.010.02 1.2 6.0 +12.0 +24.0 48.0+ 72.0 +96.0+120.0+240.0 cm avg 11 X = 56.2936 cm avg

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Step 3

Given,

...
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-0.563 m avg k 9x10 Nm2/c E =8.85x10-12s A2/m'kg

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Science

Physics

Electric Charges and Fields

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