A steel rod is stretched between two rigid walls and carries a tensile load of 5000 N at 20°C. If the allowable stress is not to exceed 130 MPa at -20°C, determine the minimum diameter of the rod? Assume a = 11.7 um(m-°C) and E = 200 GPa.

Principles of Physics: A Calculus-Based Text
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Chapter15: Fluid Mechanics
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b) A steel rod is stretched between two rigid walls and carries a tensile load of 5000N at
20°C. If the allowable stress is not to exceed 130 MPa at -20°C, determine the
minimum diameter of the rod? Assume a = 11.7 um/(m-°C) and E = 200 GPa
Transcribed Image Text:b) A steel rod is stretched between two rigid walls and carries a tensile load of 5000N at 20°C. If the allowable stress is not to exceed 130 MPa at -20°C, determine the minimum diameter of the rod? Assume a = 11.7 um/(m-°C) and E = 200 GPa
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Why is is that when I compute for the diameter, the answer is 7.9706? How was 13.22 obtained? 

Bartleby link for reference: https://www.bartleby.com/questions-and-answers/a-steel-rod-is-stretched-between-two-rigid-walls-and-carries-a-tensile-load-of-5000-n-at-20c.-if-the/5c99ed3b-d083-41be-a905-b15aa3bc8648

4x5000
=
|≈(130×106 −11.7×10×200×10²×40)
d
d = 13.22 x10 m
d = 13.22mm
Transcribed Image Text:4x5000 = |≈(130×106 −11.7×10×200×10²×40) d d = 13.22 x10 m d = 13.22mm
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