5 + 22 4 -4 -S 6 The graph above shows the base of an object. Compute the exact value of the volume of the object, given that cross sections (perpendicular to the base and parallel to the y-axis) are equiangular triangles. V = 268√3 X
5 + 22 4 -4 -S 6 The graph above shows the base of an object. Compute the exact value of the volume of the object, given that cross sections (perpendicular to the base and parallel to the y-axis) are equiangular triangles. V = 268√3 X
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter20: Ratio And Propor Tion
Section: Chapter Questions
Problem 4A: The volume V of a cube is V=s3 , where s is the length of one side. Determine the volume of a cube...
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