-5 4 0 1 0 * 0 * 0 1 0. 0. . 1 0. 8. 0. 2 0.

Q: 1 3 -4 2 0 0 0 0 0 0 0 0 -1 6. 1 -3 7 1 4 -3 0 0

A: Remark:  We know that the maximum number of linearly independent vectors in a matrix is equal to the…

Q: 0.1 0.3 2 . 3 0.9 0.1 0.8 1 0.1 0.2 0.1 4 0.9

A: Given : States :  1   ,  2   ,   3    , 4 P(Transition probability…

Q: 0.25 0.54 0.10 0.11

A:

Q: 1 2 0 0 -5 0 0 1 0 -4 0 0 0 1 2 Lo 0 0 0 0J

A:

Q: Verify that the infinite series converges.

A:

Q: 5 20 0 1 0 1 4 3 5 0 0 3 2 6 0 0 4 6 7 0 0 0 0 2]

A:

Q: 3.0 -0.5 0.6 1.5 4.5 6.0

A:

Q: 0.1 0.7 A 0.8 0.8 0.8

A: Given, P(A)=0.7, P(B)=0.7 P(C)=P(D)=P(E)=0.8 Diagram as follows- a] The system will work if- a)…

Q: 1 0 0 0 0 1 2 -6 2 -8 10 1 0 1 0 3 -2 -5 -16 |

A: We have to multiply: 1000012-60010003-22-8-5-16

Q: 2 + 0.4 + 0.08 + 0.016 +

A:

Q: 1 0 0 0 1 -1 0 0 0 -1 - (Ь.) А — 1 -1 0 0 -1 0 -1 0 0 0 0 -1 1 0 0 1 - 1

A: Given: A=100001-100-11-100-10000-1-11001 To find: Jordan Canonical form of the matrices.

Q: 1 P = 1 1.5 1.5 0 0.5 0.5 (1) P2 = (2) P4

A:

Q: Identify and graph the equation: r = 3

A: Given: The polar equation r=3, To determine: The graph of the given equation,

Q: P(0< z < ze)=0.4573

A:

Q: P(z -1.16) = P(z 2.61) = P(0 < z < 2.32)

A: We will use Standard Normal table to find the required probabilities.

Q: 6s – 4 s' + 4s – 12 6s – 4 s° +4s+ 20 ||

A:

Q: -0.5] H-B-E 0.5 0.5 0.5 0.5 0.5 -0.5 -0.5 0.5 -0.5 0.5 -0.5

A: Follow the steps.

Q: 2.0 1.5 1.0 0.5 0.2 0.4 0.6 0.8 1.0

A:

Q: 3. 1.1 1.05 6. -3/4 -.75

A:

Q: 1 0 1 0 -1 1 0 1 -1 0 0 1 0 -1 0 1]

A:

Q: 2 2 4 0 1 3 0 1 1 00 A = |4 1 1 0

A: X=72-1-1

Q: Find s12 for the series 2 + 8 + 32 + 128 + …

A: ? Answer is  11,184,810

Q: 0 0 0 0 30 0 0 2 0 0 0 0 1 0 0 0 4 Evaluate: 0

A: The determinant of a matrix is found by expanding the determinant along a particular row or column…

Q: \0.8 0.3 ] 0.9 0.2 0.7 T = 0.1 =

A: Given

Q: P(-1.18<z≤ _________ )=0.6327   2. P ( ____ ≤z<0.85)=0.6363

A: we have to find probability for normal distribution.

Q: 2x-26(5-+ 25=0 1 25 0 2文+1 26 (5*) +5 = 0 2. 3(3)+e(3*)-3= 0 12

A:

Q: P(x) 0.05 0.25 0.4 0.06 12. 1 3 4 5 P(x) 0.06 0.23 ? 0.35 0.05 13. 3 4 5 2 P(x) 15 15 14. X. 3 4 5…

A: We have given that the probability distribution in tabulation form. We know that the sum of…

Q: S7=1−1/√2+1/2−12/√2+14−14/√2+1/8.

A: Given:

Q: 5 fy 4 3 2 -1.5 -1 -0.5 0.5 1 1.5 |

A: Consider the given graph: Here, it represents an exponentially increasing curve.   Let: y=abx  ……1…

Q: : p(y-2|<10) p(z <2) =0.9772 y- N(2,25) 0.4594 0.5944 O 0.9544

A: It is known that, Z score= (y-mean)/standard deviation. Given that, Mean= 2 and variance= 25  So…

Q: P(z-1.45)= P(-1.88<z<0.5)= P(-0.69<z<0.69)=

A:

Q: H:p0.79

A:

Q: Compute AB by block multiplication, using the indicated partitioning.

A: We will assume the by parts to be some variables so as to carry out easy matrix multiplication.

Q: P(Z ≤ 0.77) = [] P(Z > 1.36) = [ P(−0.70 < Z < 2.06) = |

A: Given P(z≤0.77)

Q: 1.35 0.38 0.52

A:

Q: 0.6T 0.4+ 0.2- 0.0- -0.2+ -0.4+ -0.6+ -0.8+ -1.0- + + 3 + 4 + 1 8. 9. +5 2. Residuals

A: Solution: From the given plot, it can be observed that there is no particular pattern in the data.…

Q: 3 0.00 50)3.0 0 50 -

A: The given expression is 350. Divide as follows.

Q: 10 -2 1 0 1 4 0 0 - 15 10 -2 1 0 1 4 0 0 5 -15

A:

Q: correct answer)? 0 0 1 -2 0 1 2 0 2 0 1 1 1 0 0 1 0 -2 0 1 1 0 -2 0 1

A: An elementary matrix is a square matrix that has been obtained by performing an elementary row or…

Q: -2 6 Find A for A = 3 -3 4 -7 3 s 5/12 /5 1/6 L/S 16 7/20 1/10 1/10 Ans.

A: To find the inverse of matrix A.

Q: 1 -2 0 2 0 0 1 5 0 -3 0 0 0 1 0 0 0 0 1 1

A: Given Augmented Matrix:- 1-2020100150-30000160000001-110 To solve the augmented matrix

Q: 0-0.9 40 1.0-1.9 19 2.0-2.9 15 3.0-3.9 20 4.0-4.9 12 5.0-5.9 11

A: Since the question has multiple sub parts we will solve the first part only. Please resend the…

Q: Z• 0 • 1 6 0.00 0.25 0.50 0.75 1.00 4.

A:

Q: p(-1.80<z<0.20)

A: We have to find P(-1.80&lt;z&lt;0.20)  z is standard normal variable with mean 0 and standard…

Q: 0 |-6 4 13 11 18 17 0 31 9 0

A:

Q: of 5 5 6 7 9. P(X = x) 0.2 0.2 0.2 0.1 0.3 8.

A:

Q: 1 2 4 1 0 2 1 7. 7. 3. 3.

A: We find Least-Square solution by using theorem.

Q: P(-0.63<Z<1.85)=

A: Given : z₁=-0.63 z₂=1.85

Q: (-0.1)-금 (30)+ (150) f-0.1)= 2 3. (-0.1) 3(-0.1) -0.)(120)=683 6. 4

A: Here we have to go back to just previous step were we have function,…

Q: Compute the determinant of

A: We know that determinant of upper (lower) triangular matrix is the product of the diagonal entries.

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.