-5-4 -3 -2 -1 1 4 -5 4 -3 -2 -1 1. 3 4 -2 -1 2 3 4 -4 -3 -2 4 5

Q: :). -5 -3 -7 1 17 - 70 -5 9. 10 35 -5

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Q: -5×(-4+3) 6 (-3) -10 + (-10) 25 X -21 + 7

A: To evaluate an algebraic expression:  1. Follow BODMAS rule. 2. Multiplication of two negative…

Q: -1 0 12 0 1 0. -3 -1 12 1 -3 -3 Ans. -1, ;-5, ; 3, -1 -4 1 1 -4 -1 1 3. ..

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Q: -10 -7 -6 7 -8 -4 4 2 2 -9 1 9 5 6 3 -1 [A] = [D] = -5 3 -4 -3 7 8 -3 1 -8 -2 10 -1 -2 -7 -5 10 3[A]…

A: Explanation of the answer is as follows

Q: -4 1 -6 1 A = 1 -1 0 -4

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Q: (-3.3) 7 6 5 4 3 2 (-3,2) 1 -6 -5 -4 -3 -2 -1 -2 -3 -4 -5 -6 7 1 2 3 4 5 6 7 (2)

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Q: ements. -4 16 | 20] 2 2 1 -4 2] -9 2 [1 -4 -34 -43 10슈 ↑ 1 1 1

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Q: х -1 2 1 -1 х 2 1 = 0 х 1 |-1 2 -1 2 1

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Q: 6 5 3 1 + -4 -2 -1 3 4 5 -2 -3 - -4 2. + 2.

A: Let us use Newton Algorithm to find the polynomial. The curve given passes through the points…

Q: 1 -2 0 1 3 1 1 -1 2 6 4 1 -4 13

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Q: 1 -1 1 1 4 -4 3 6 2 -2 1 3

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Q: -10 -9 8 -6 -5 -4 -3 -2 5 3- 2 1 -1 0 -1 -2 -3 + -4 -5 1 2 3 6 4 20

A: We have to find the value of the given definite integral according to the given information

Q: 4 -5 4 0 -5 -1 1 В. С 4 -5 0 2 -2 0 1 4 1 -2 2 ЗВ - С %—

A: Solve the two matrices B and C, in the form of 3B-C.Multiply the scalar product 3 with a matrix B,

Q: 2 -5 -4 -3 -2 -1 -3 -41 -5 3. 2. 3. 2:

A: First of all write the roots of given function:-x=-3,-3,0 are the rootsso factors will be

Q: -6 8 -2 8 -2 A= C= -5 -3 -5 -9 -4 7 -4 -2 2 -5 1 B = -8 -2 -3 -9 6

A: As per bartleby guidelines we only give first three questions answers.

Q: 2 0 -4 6| 4 1 0 2 6 -1 -3 8 9 1

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Q: -4-3|4-4*2|

A: This is a basic question including a modulus function. in this |4-4*2|=|4-8|=|-4| Modulus function…

Q: Find the determinant of the matrix.

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Q: -1 4 -7 -6 10 3 -2 -4 9 -8 [B] [F] -9 -3 -10 6 4 -2 -6 10 -10 2 4[B] – 2[F]

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Q: -10 -9 -8 -7 -6 -4 -3 -2 -11 1 4 5. 10 00 6. %2. 2. 3. 2. 1. 2. 5.

A: Find two points on line then find equation of line by standard form of line

Q: -10 -9 N -8 -6 -5 10 6 8 7 6 5- 4 3 9 1 0 2 3 4 6 8 9 10 Т

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Q: 1 1 -2 16. Л 3 3, А — -1 1 0 1 -1

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Q: Evaluate D = 1 3 1 -2 2 0 -2 -4 ବ -1 2 1 5 0 3 1 6

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Q: 4 -10 -8 -6 -2 12 4 6. 10 -2 -4 -6 -8 -10 8. 8 2.

A: Concept: From the given graph we shall determine the place of intersection. The coordinates of the…

Q: In Problems 7–14, find the value of each determinant.

A: 7. We have to find the value of the following determinant: 64-13 Then we get, 64-13=6×3-4×-1=18+4=22…

Q: [-3 10] 14 B = 10 [5 -2 17 -1] C = A =-5 2 D=[-11 8 -5] -8 3 -4 2 14 -6 -8

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Q: 2(6х- 5) 1 6 -5 4 -3 -2 -1 1 4 6 -30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: 1. [3 1 2] 2. [-1 2 -3] 3. [10 -5 2] 4. [-4 -5 -3]

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Q: - 5 1 4 2 1 0-3 -4 Add: -6 -1 -5 6 4 7 0. -2

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Q: 4 4 - 5 3 - - 5 -1 %D 5 -5 2 3 1 4.

A: Simply use the concept of matrix multiplication. Multiply and add each element of each raw to…

Q: 4 -3 -2 -1 0 2 6. 8 -1 -2 -4 -5+ -6+ -7 9 5 4. 3. 5

A: In this question we have to find the equation for the function.

Q: -1 -3 -1 1 -2 4 -3 1 1 3 2 3.) -2 4 -3 -4 2 0 -4 2 0 4 1 -1

A:

Q: -1 -5 3 -2 5 2 3 C = 0 2 -2 1 -2 2 -7 -4 1 2 7 -1 4 5 2. 3.

A: Given matrix is, C=2-1-53-252030-2102-232-7-4127-145 Apply R2→5R1-2R2.…

Q: -7-6-5-4-3-2- 6 5 4 3 -2 -5. -6. H 1 2 3 4 5 6 7

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Q: (-2. 35) (2. 3.5) (-4, 0) (-2. -3.5) (2. -3.5) 至

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Q: -1 2 -3 1 2 1 C. -1 2 -3 1 1 6 -1

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Q: 5 2 0 3 1 3 В с 4 -4 -1 0 5 0 1 1 1 -4 СА

A: Given,

Q: - 3 -4 -4 3 -4 -5 Subtract: 4 8 8 2 1 - 5 7 7 7 6. -6 -5 |

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Q: -1.0 1 3. 5 6 -4-3-2 1 23 4 56 -2 -3- -4 -5 -61 (a) (b) a 654 32 6. 543N-

A: . If a vertical line is moved across the graph and, at any time, touches the graph at only one…

Q: -2 3 -5 2 3 3 2 3 1 1 -4

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Q: 1 - 3 3 3 -1 4 -3 - 3 40. -2 1 1 1 0 0

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Q: h(-7) =| %3D 6- 5+ 4+ h 3- 2 -7 -6 -5 -4 -3 -2 1 2 3 45 6 7 -2 3+ -4+ -5 -6- -7- 1.

A: The graph of the function is given. Every point on the graph have coordinates (x, h(x)).

Q: (1, -1) 4 5 6 7 8 9 10 11 12 -12-11-10 -9 -8 - -6 -5 -4 -3 -2 -1, (-3, -2). -2 -3 -4 -5

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Q: 1 2 -3 -2 0 4 -1 -4 3 2 A = 2 4 1 -2 -2 3 4 -1 3

A: The given matrix is: A=   12-3   4-1-20-4   3   2   24   0   1-2-23   4-1   3

Q: 1. -3 -2 -1 1 2 3 14 10 2 -2 -6 -10

A: For a graph to be linear the difference of values of y should be the same.…

Q: + + -5 -4 -3 -2 -1 у 5+ 4+ 3+ 2+ 10 О -1+ -2+ -3+ -40 −5+ 1 2 3 4 5 X

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Q: 1-. 5x <35 -2 (х-3) (х+3)* (*+1(5-х) 7-3. 2х - 3 <4 x-1 2.4, 25. -23х -5 - 8<-20

A: