(5) Consider a gas that follows the equation of state NRT aN? p = V – bN V2 8a This is called van der Waals gas (a, b > 0). For temperatures T > Tc = p(V) is a 27RB monotonic decreasing function. Assume T > Tc and Cy = 3NR/2. %3D Consider an insulated box with volume V, . The box was divided by a wall. One of the compartments had volume V, at temperature To, filled with van der Waals gas of amount N, and the other was vacuum. The system was in equilibrium. (a) The wall was removed abruptly. The gas expanded and occupied the entire box. This process is called adiabatic free expansion. The temperature in the box is now T, in equilibrium. What is T – T,? (b) The internal energy of the gas does not change by adiabatic free expansion. Why? (c) Instead of the abrupt removal, the wall was moved through adiabatic and quasi-static process, and the gas expanded to the entire volume of the box. The temperature in the box is now T2 in equilibrium. What is T2? (d) Show T, > T2, using the arguments of the second law of thermodynamics.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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(5) Consider a gas that follows the equation of state
NRT
aN?
p =
V – bN
V2
|
8a
This is called van der Waals gas (a,b > 0). For temperatures T > Tc =
p(V) is a
27RB
monotonic decreasing function. Assume T > Tc and Cy = 3NR/2.
Consider an insulated box with volume V, . The box was divided by a wall. One of the
compartments had volume Vo at temperature To, filled with van der Waals gas of amount N, and
the other was vacuum. The system was in equilibrium.
(a) The wall was removed abruptly. The gas expanded and occupied the entire box. This
process is called adiabatic free expansion. The temperature in the box is now T, in
equilibrium. What is T, – T,?
(b) The internal energy of the gas does not change by adiabatic free expansion. Why?
(c) Instead of the abrupt removal, the wall was moved through adiabatic and quasi-static
process, and the gas expanded to the entire volume of the box. The temperature in the box
is now T, in equilibrium. What is T2?
(d) Show T, > T2, using the arguments of the second law of thermodynamics.
Transcribed Image Text:(5) Consider a gas that follows the equation of state NRT aN? p = V – bN V2 | 8a This is called van der Waals gas (a,b > 0). For temperatures T > Tc = p(V) is a 27RB monotonic decreasing function. Assume T > Tc and Cy = 3NR/2. Consider an insulated box with volume V, . The box was divided by a wall. One of the compartments had volume Vo at temperature To, filled with van der Waals gas of amount N, and the other was vacuum. The system was in equilibrium. (a) The wall was removed abruptly. The gas expanded and occupied the entire box. This process is called adiabatic free expansion. The temperature in the box is now T, in equilibrium. What is T, – T,? (b) The internal energy of the gas does not change by adiabatic free expansion. Why? (c) Instead of the abrupt removal, the wall was moved through adiabatic and quasi-static process, and the gas expanded to the entire volume of the box. The temperature in the box is now T, in equilibrium. What is T2? (d) Show T, > T2, using the arguments of the second law of thermodynamics.
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