5) ΔLMN= ΔDEC 6) ΔTSR ΔLJK R. S. ZN = ? ZS = ? 7) △XWY츠 ΔUTS 8) ΔBACAMKL VA ZY ? ZB =?
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- ONLY parts L, M, and N please show work tooA particle travels along a path from (0, 0) to (3, 4). What is thedisplacement? Can the distance traveled be determined from the information given?Suppose that an equilateral triangle with sides of length 9 ft contains 10 points randomly placed. Use the pigeonhole principle to prove that 2 of those points are at least 3 ft apart.
- Since PN¯¯¯¯¯¯¯¯ bisects MO¯¯¯¯¯¯¯¯¯, that means that PN¯¯¯¯¯¯¯¯ ≅PN¯¯¯¯¯¯¯¯ because of the definition of a triangle.Because PN¯¯¯¯¯¯¯¯⊥ MO¯¯¯¯¯¯¯¯¯ that means that ∠ONP and ∠MNPare both right angles because of the the definition of perpendicular. This means that ∠ONP ≅ ∠MNP because all right angles are congruent. Also, by the Reflexive Property of Congruence, Response area.Based on these three pairs of congruent corresponding parts, △ONP ≅ △MNP, based on theFind the area of the parallelogram that has u = (1, 3, 0) and v = (−1, 0, 2) as adjacent sides.In , triangle ABC, lines CD is perpendicular to AB, and in traingle XYZ, lines ZW is perpendicular to XY. If AB = XY and CD = ZW, then: a. Traingle ABC is congruent to triangle XYZ b. Triangle ABC and XYZ have the same perimeter c. Triangle ABC is simillar to XYZ d. Triangle ABC and XYZ have the same area.
- Derive the frenet frame, curvature and torison of the binormal indicatrix of hypocycloid?The article cited in Exercise 20 also gave the followingvalues of the variables y 5 number of culs-de-sac andz 5 number of intersections:y 1 0 1 0 0 2 0 1 1 1 2 1 0 0 1 1 0 1 1z 1 8 6 1 1 5 3 0 0 4 4 0 0 1 2 1 4 0 4y 1 1 0 0 0 1 1 2 0 1 2 2 1 1 0 2 1 1 0z 0 3 0 1 1 0 1 3 2 4 6 6 0 1 1 8 3 3 5y 1 5 0 3 0 1 1 0 0z 0 5 2 3 1 0 0 0 3a. Construct a histogram for the y data. What proportionof these subdivisions had no culs-de-sac? Atleast one cul-de-sac?b. Construct a histogram for the z data. What proportionof these subdivisions had at most five intersections?Fewer than five intersections?9, 10, 19, 20 using Gauss-Jordan Elimi