5 Each of 100 individuals of a mammal speciesfrequency with which the animals chose each ofFood item Sample 1 Sample 2was placed in enclosure containing equalamount of each of five different foods. Thethe foods was:(01820177204623452418(a) Calculate the Shannon-Wiener diversityindex and evenness index for each sample.(b) Which sample has higher diversity?(c) Describe a sample frequency (of n 100)that achieve the highest diversity

Shannon-Wiener diversity index is the index to find the amount of diversity in the given sample.…

Answered: 5 Each of 100 individuals of a mammal…

Biomedical Instrumentation Systems

1st Edition

ISBN:9781133478294

Author:Chatterjee

Publisher:Chatterjee

Chapter13: Artifacts And Noise In Medical Instrumentation

Section: Chapter Questions

Problem 7P

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TRUE or FALSE: I expect for genetically identical animals thta have been reared in similar conditions to have a similar SD for any paraeter that I decide to measure compared to genetically diverse animals that have been grown in a variety of natural environments.
Suppose a man is heterozygous for heterochromia, an autosomal dominant disorder which causes two different-colored eyes in an individual, produced 25-offspring with his normal-eyed wife. Of their children, 14 were heterochromatic and 11 were-normal. Calculate the chi-square value for this observation. x² = Identify the statement that best interprets the results of the chi-square analysis. Refer to the chi-square distribution table to identify the statement that best interprets the chi-square results. It is not unusal that a heterozygous man produced 14 out of 25 offspring with heterochromia. The total number of normal offspring is significantly lower than expected. It is unusual that a man with heterochromia had 14 out of 25 offspring with heterochromia. There is a significant difference between the observed number of offspring with heterochromia and the number of offspring that were expected to have heterochromia.
1). The p-value for this test is . 072. Do we reject the null hypothesis?2). Is there sufficient evidence to conclude that there is a statistically significant difference in mean weight between the different NYHA groups?3). Pretend for a moment that the resulting p-value was 0.02. Do we reject the null hypothesis in this case? Why or why not? If we were to reject the null hypothesis, we would conclude that there is sufficient evidence to suggest a statistically significant difference in mean weight between the NYHA groups. The NYHA variable has four levels: would we know which of the four NYHA group means gave the statistically significant result?
Please answer atleast 3, I know your guidlines only allow you to answer 3. But sometimes, some tutors only answer 1. Please don't cheat, bartleby is expensive and i'm only a student. it's hard to afford it :(
atural Selection - DA # 3 Flgure A shows the color of deer mice (Peromyscus maniculatus) In the Nebraska Sand Hills (white area) and the rest of the State (grey area). Mice are shown on the habitat they are not nomally found on. The color of the Sand Hills Is shown below the light-colored mouse (normal habltat), while the color of the ground in the rest of the State is shown below the dark-colored mouse. Figure B shows the phenotyplc difference in the hair shaft of the wild-type and the light-colored (wideband) mice. Figure C shows the expressilon levels (MRNA) of the Agouti alleles responsīble for the phenotype seen in figure B. a+= wild-type Agouti alele, a-= a deletion of the Agouti allele, awb = wideband Agouti allele mutation, and the black rectangles undermeath each bar is the relative difference in the hair shaft band phenotype. Wder band means lighter hair color in the deer mice. b. The Sand Hills were created by volcanic activity 15,000-8,000 years ago. How were the deer mice…
help and explain which answer is correct
17) In chi-squared analysis... A. If the observed data exactly agree with the predictions of the hypothesis, then we expect the p-value to be (1.0, 100, less than 0.05, 0, greater than 0.05) B. If the observed data closely agree with the predictions of the hypothesis, then we expect the p-value to be (1.0, 100, less than 0.05, 0, greater than 0.05) C. If the observed data do not at all agree with the predictions of the hypothesis, then we expect the p-value to be (1.0, 100, less than 0.05, 0, greater than 0.05) Chose one from the parenthesis for each question.
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part B ONLY
page - Columbus State Uni X content/2622738/viewContent/50155728/View + Calculating the Value of Chi-Square Once you've defined the null hypothesis (and know what you're testing!), you can finally calculate the chi-square value based on your observed data and the expected distribution. There are many statistical software packages and free web-based applications that will automate the calculation for you, but it's important to understand the calculation to understand the meaning of the calculated value. Here, we'll walk through it using a calculation table. This is Mendel's historic data for the F2 generation of monohybrid cross for flower color. Recall that he expected to see in the F2 generation a ratio of 3 purple : 1 white. Chi-square calculation for data from a monohybrid cross with an expected 3 purple : 1 white ratio. Outcomes Observed (0) Expected (E) O-E (0-E)2 (O-E)²/E Purple White Totals 705 224 929 X²= The first step is to calculate the expected (E) values for purple and…
The following table shows the distance moved in an SDS-polyacrylamide gel by a series of marker proteins of known relative molecular weight. a. If the tracking dye had moved a distance of 90.0 mm, calculate linear regression parameters such as linearity coefficient (r), the slope (m), and the y-intercept (b). Protein MW (Da Distance moved (mm) Transferrin 78 000 6.0 Bovine serum albumin 66 000 12.5 Ovalbumin 45 000 32.0 54.0 Trypsinogen Myoglobin Lysozyme Cytochrome c 24 000 17 800 69.0 14 300 79.0 12 400 86.5 Proliferating cell nuclear antigen (PCNA) acts as a homotrimer of three identical subunits and helps increase the processivity of leading strand synthesis during DNA replication. It has a molecular weight of 36.0 kDa. Under the reducing conditions of the sample buffer, the disulfide bridges linking the subunits are reduced and thus the monomer chains are seen on the gel. b. Calculate the Rf of the single band of PCNA when subjected to SDS-PAGE. c. Predict the distance (in mm)…

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