5. 2.6477 g of the reducing agent FeSO4 was titrated to the equivalence point with 17.25 mL of a KMNO4 solution. a. Calculate the molarity of the KMNO4 solution. 2.L477 FESO4 x L mol 151-915 Imol Khga 5 molFe = 0.2021 M RMOg 0.01725 L * b. What volume (in mL) of the KMNO4 solution would be needed to react with 12.50 grams of 30.0 % H2O2 solution?

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