5. A ball of mass m = 0.275 kg swings in a vertical circular path on a string L= 0.850 m long as in the Figure. (a) What are the forces acting on the ball at any point on the path? (b) Draw force diagrams for the ball when it is at the bottom of the circle and when it is at the top. (c) If its speed is 5.20 m/s at the top of the circle, what is the tension in the string there? (d) If the string breaks when its tension exceeds 22.5 N, what is the maximum speed the ball can have at the bottom before that happens?

5. A ball of mass m = 0.275 kg swings in a vertical circular path on a string L= 0.850 m long as in the Figure. (a) What are the forces acting on the ball at any point on the path? (b) Draw force diagrams for the ball when it is at the bottom of the circle and when it is at the top. (c) If its speed is 5.20 m/s at the top of the circle, what is the tension in the string there? (d) If the string breaks when its tension exceeds 22.5 N, what is the maximum speed the ball can have at the bottom before that happens?

Name: 5. A ball of mass m = 0.275 kg swings in a vertical circular path on
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Description: 5. A ball of mass m = 0.275 kg swings in a vertical circular path on astring L = 0.850 m long as in the Figure.(a) What are the forces acting on the ball at any point on the path?(b) Draw force diagrams for the ball when it is at the bottom of theci

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter8: Conservation Of Energy

Section: Chapter Questions

Problem 28AP: Why is the following situation impossible? A softball pitcher has a strange technique: she begins...

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Why is the following situation impossible? A softball pitcher has a strange technique: she begins with her hand at rest at the highest point she can reach and then quickly rotates her arm backward so that the ball moves through a half-circle path. She releases the ball when her hand reaches the bottom of the path. The pitcher maintains a component of force on the 0.180-kg ball of constant magnitude 12.0 N in the direction of motion around the complete path. As the ball arrives at the bottom of the path, it leaves her hand with a speed of 25.0 m/s.
Part of riding a bicycle involves leaning at the correct angle when making a turn, as seen in Figure 6.36. To be stable, the force exerted by the ground must be on a line going through the center of gravity. The force on the bicycle wheel can be resolved into two perpendicular components—friction parallel to the road (this must supply the centripetal force), and the vertical normal force (which must equal the system's weight). (a) Show that (as defined in the figure) is related to the speed v and radius of curvature r of the turn in the same way as for an ideally banked roadway—that is, =tan1v2/rg (b) Calculate for a 12.0 m/s turn of radius 30.0 m (as in a race). Figure 6.36 A bicyclist negotiating a turn on level ground must lean at the correct angle—the ability to do this becomes instinctive. The force of the ground on the wheel needs to be on a line through the center of gravity. The net external force on the system is the centripetal force. The vertical component of the force on the wheel cancels the weight of the system while its horizontal component must supply the centripetal force. This process produces a relationship among the angle , the speed v, and the radius of curvature r of the turn similar to that for the ideal banking of roadways.
1. A car enters a level, unbanked semi-circular hairpin bend with a radius of 300 m at a speed of 120 km/h.The coefficient of friction between the tyres and the road is U = 0.250. If the car maintains the constant speedof 120 km/h, show that the likely fate for the car will be to veer toward the outside of the circle. 3.2(a) A block of mass m on a horizontal frictionless surface is attached to a light spring with force constant k.The block is initially at rest at its natural (equilibrium) position when a force P acting parallel to the surface, isapplied to the block as shown. What is the speed of the block when it is at position x from its equilibriumposition? (5) 3.2(b) If the block has a mass of 12 kg, the spring constant has a value of 0.80 kN/m when the block is initiallyat rest at the equilibrium position when a force of magnitude P = 80 N acting parallel to the surface is appliedto the block. What is the speed of the block when it is 13 cm from the equilibrium position?
1.If the sling used a 1.50m string to whirl a 0.0350kg pebble to a horizontal circle, what is the tension on the cord if the pebble makes one revolution in 1.20s?2. A 3000kg minitruck rounds a 200m level curve. The maximum frictional force between the road and the tires is 5000 N. Will he safely make it if he moves at19.0m/s (about 70kph)?3. In a NASCAR competition, a car can negotiate the 60.0 m radius curve at a maximum speed of 120 kph. At what angle should the curve be banked?
A motorcyclist in the Globe of Death, pictured here, rides in a 2.2-m-radius vertical loop. To keep control of the bike, the rider wants the normal force on his tires at the top of the loop to equal or exceed his and the bike’s combined weight. What is the minimum speed at which the rider can take the loop?
A nylon string is rated to withstand a force/tension of 100 N. A boy decided to play with this string to whirl a 0.8-kg object in a horizontal circle of radius 3.5 m. As the boy increases the speed of the object, up to which speed the string will remain intact? At that moment, what is the centripetal acceleration of the object? Suppose the boy decided to break the object in half (the new mass become half the original mass), and extend the string radius to 7 m using the same quality string (to withstand 100 N force). What changes will occur to the maximum circular velocity and centripetal acceleration?
1. A road with a radius of 75.0 m is banked so that a car can navigate the curve at a speed of 13.2 m/s without any friction. When a car is going 27.6 m/s on this curve, what minimum coefficient of static friction is needed if the car is to navigate the curve without slipping? 2. A spy satellite is in circular orbit around Earth. It makes one revolution in 2.70 h. Mass of Earth is 5.974 × 1024 kg, radius of Earth is 6371 km and Gravitational constant G is = 6.674 × 10−11 N·m2/kg2. A) How high above Earth’s surface is the satellite? in KM B) What is the satellite’s acceleration? in m/s2
On a highway curve with radius 44 m, the maximum force of static friction (centripetal force) that can act on a 1,173-kg car going around the curve is 8,327 N. What speed limit should be posted for the curve so that cars can negotiate it safely?
A 1 500-kg car moving on a flat, horizontal road negotiates a curve as shown in the overhead view in 6.4a. If the radius of the curve is 35.0 m and the coefficient of static friction between the tires and dry pavement is 0.523, find the maximum speed the car can have and still make the turn successfully.
Question: A 0.24 kg stone is attached to a string and swung in a circle of radius 0.59 m on a horizontal and frictionless surface. If the stone makes 0.40 revolutions per second, the tension force of the string on the stone is ________ N. Comments: How do you come up with the equation to solve this?
6. A motorcycle rounds a banked turn of 7% with a radius of 85m. If the friction coefficient between the tires and the road surface is 1.2 and the mass of the motorcycle with rider is 260 kg, how fast can the motorcycle round the turn? Assume g=9.8m/s2.
An owner of a speedboat loves high speed but doesn't want to go anywhere. So he tethers the speedboat to a fixed buoy by a strong cable of length 40.0 m40.0 m, which supplies all the centripetal force to run the boat in circles around the buoy. When the tension in the cable is steady at 13500 N13500 N, with what force is the boat's engine pushing the boat? Assume that the mass of the speedboat (including the driver) is 645 kg645 kg. Take the water's drag force to be (450 kg/m)×v2(450 kg/m)×v2, where vv denotes the boat's speed. Ignore any drag force on the cable. Be sure to include the free-body diagram for the boat.