Aid.coSole et. Al Leather Puffer...ЯHome0AssignmentsCurrent Time: 11:20:38 PMgeneral.physics.rutgers.eduOc Awards - Google DocsPractice AssignmentG duke ellington - Google...HomeworkOpening Ceremony Itiner...cil6 ccilⒸGLog OutTime Left: 1 days 0 hours 35 minutes5. A basketball player is standing on the floor 14.5 m away from the basket. The height of the basket is 3.10 m, and heshoots the ball at 50.0° with the horizontal from a height of 1.90 m. At what speed must the player shoot the ball so thatit goes through the hoop without striking the backboard?m/sR General Physics 203+

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Answered: 5. A basketball player is standing on…

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter12: Relativity, Particle Physics, And Cosmology

Section: Chapter Questions

Problem 4Q

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Assignments
Current Time: 11:20:38 PM
general.physics.rutgers.edu
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cil6 ccil
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5. A basketball player is standing on the floor 14.5 m away from the basket. The height of the basket is 3.10 m, and he
shoots the ball at 50.0° with the horizontal from a height of 1.90 m. At what speed must the player shoot the ball so that
it goes through the hoop without striking the backboard?
m/s
R General Physics 203
+

Expert Solution

Introduction:

Projectile motion and equation of motion:

When an object is thrown at angle $θ$ from the horizontal surface, object follows a curved path before reaching to ground.

The total time of flight (t in s) is the time during which it remains in the projectile motion.

Object has two components of initial velocities: First component is horizontal velocity (v_x)and second component is vertical velocity (v_y).

v_x will remain constant through out it's flight time (t)= v cos $θ$
v_y is the initial velocity and final velocity can be calculated based on constant acceleration due to gravity in vertical direction and for that equation of motion is used.

Equation of motion:

It is used to establish relationship between distance travelled, initial & final velocities during the time (t) travelled under constant acceleration.

Mathematically,

$v = u \pm a t v^{2} \pm u^{2} = 2 a s s = u t \pm \frac{1}{2} a t^{2}$

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