5. A proton (q=1.6x1019 C, m=1.67x1027 kg) moves in auniform magnetic field given as B=(1 T) i. At time t=0 theproton has velocity components vx-1.50x10°m/s, vy-0,and vz=2.00x10°m/s. What is magnetic force acting onthe proton?a) o F=(3.20x10-14 N)jb) o F=(0.77x10-14 N)j9o F=(1.60x10-14 N)jd) O N)jF=(1.80x10-14e) o F=(2.60x10-14 N)jLeave blank

Given Q = 1.67*10-19 C V = 150000 i + 0j + 200000 k B = 1 i

5. A proton (q=1.6x10-19 C, m=1.67x1027 kg) moves in a uniform magnetic field given as B=(1 T) i. At time t=0 the proton has velocity components Vx=1.50x10Pm/s, vy=0, and vz=2.00x10°m/s. What is magnetic force acting on the proton?

5. A proton (q=1.6x10-19 C, m=1.67x1027 kg) moves in a uniform magnetic field given as B=(1 T) i. At time t=0 the proton has velocity components Vx=1.50x10Pm/s, vy=0, and vz=2.00x10°m/s. What is magnetic force acting on the proton?

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter11: Magnetic Forces And Fields

Section: Chapter Questions

Problem 60AP: An electron is projected into a uniform magnetic field (0.5i+0.8k)T with a velocity of...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

5. A proton (q=1.6x1019 C, m=1.67x1027 kg) moves in a
uniform magnetic field given as B=(1 T) i. At time t=0 the
proton has velocity components vx-1.50x10°m/s, vy-0,
and vz=2.00x10°m/s. What is magnetic force acting on
the proton?
a) o F=(3.20x10-14 N)j
b) o F=(0.77x10-14 N)j
9o F=(1.60x10-14 N)j
d) O N)j
F=(1.80x10-14
e) o F=(2.60x10-14 N)j
Leave blank

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