5. A steel tape is 150 m. long at a standard pull of 65 N. Compute the pull correction in mm if during measurement the applied pull is 42 N. The tape has a cross sectional area of 3.18 mm² and a modulus of elasticity E = 200,000 MPa. A. -5.772 C. -4.321 B. -5.425 D. -5.936 6. The volume of a closed cylinder is numerically equal to its lateral area. The height is 18 m. Find the volume in m³. A. 198.7 C. 321.4 B. 257.8 D. 226.2 7. The offset distance from PC to PT of a simple curve is 24 m. The angle of intersection of the tangents is 19.5°. If the stationing of PT is 12 + 365.24, what is the stationing of PI? A. 12+295.47 SEO C. 12+293.34 B. 12+296.32 10 D. 12 + 294.73 C

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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5. A steel tape is 150 m. long at a standard pull of 65 N. Compute
the pull correction in mm if during measurement the applied
pull is 42 N. The tape has a cross sectional area of 3.18 mm²
and a modulus of elasticity E = 200,000 MPa.
A. -5.772
C. -4.321
B. -5.425
D. -5.936
6. The volume of a closed cylinder is numerically equal to its
lateral area. The height is 18 m. Find the volume in m³.
A. 198.7
C. 321.4
B. 257.8
D. 226.2
7. The offset distance from PC to PT of a simple curve is 24 m.
The angle of intersection of the tangents is 19.5°. If the
stationing of PT is 12 + 365.24, what is the stationing of PI?
A. 12+295.47
SEC. 12 + 293.34
B. 12 + 296.32
D. 12 + 294.73
T
Transcribed Image Text:5. A steel tape is 150 m. long at a standard pull of 65 N. Compute the pull correction in mm if during measurement the applied pull is 42 N. The tape has a cross sectional area of 3.18 mm² and a modulus of elasticity E = 200,000 MPa. A. -5.772 C. -4.321 B. -5.425 D. -5.936 6. The volume of a closed cylinder is numerically equal to its lateral area. The height is 18 m. Find the volume in m³. A. 198.7 C. 321.4 B. 257.8 D. 226.2 7. The offset distance from PC to PT of a simple curve is 24 m. The angle of intersection of the tangents is 19.5°. If the stationing of PT is 12 + 365.24, what is the stationing of PI? A. 12+295.47 SEC. 12 + 293.34 B. 12 + 296.32 D. 12 + 294.73 T
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