5. Complete the square to determine whether the graph of the equation is an ellipse, a parabola, or a hyperbola. Then sketch the graph of the conic section. If the graph is an ellipse, find the coordinates of its center, vertices, and foci. If it is a parabola, find the coordinates of the vertex and focus and the equation of the directrix. If it is a hyperbola, find the center, vertices, and asymptotes. Include the equations of any asymptotes. 4y2 – 25x² – 24y – 64 = 0

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A: 3x2+4y2-12x-24y+48=0 3x2-12x+4y2-24y+48=0 3(x2-4x)+4(y2-6y)=-48…

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A: Equation of the ellipse gives: 25x2+16y2=16x216/25+y2=1

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Q: find the vertices, foci, center (if an ellipse or a hyperbola), and asymptotes (if a hyperbola).x^2…

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A: x2+3y2+9z2=1 On simplification, we get ⇒x21+y213+z219=1⇒x212+y2132+z2132=1⇒x12+y132+z132=1

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Q: Graph the conic section with the given equation 9x2 - 4y2 = 36.For ellipse, find the foci. For…

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A: x2+16=4y2+2x On simplification, we get x2+16=4y2+8x⇒x2-8x+16-4y2=0⇒x-42-4y2=0⇒x-424-y-021=0

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A: 9x2+4y2+36x-24y-36=0⇒9x2+36x+4y2-24y=36⇒9x2+4x+4y2-6y=36⇒9x2+4x+4+4y2-6y+9=36+36+36⇒9x+22+4y-32=108⇒…