5. In lab, you need to prepare at least 100 mL of each of the following solutions. Explain how you would proceed using the given information. Like a lab manual, your answer should provide instructions in complete sentences, indicating specific masses, volumes, glassware, and equipment to be used. Your available chemicals include KCl(s), NAOH(s), C,H12O6(s), H2O(1), and CH;OH(1). a. 2.0 m KCl in water (density of H2O = 1.00 g/cm') b. 15% NaOH by mass in water (d = 1.00 g/cm') c. 25% NaOH by mass in CH3OH (d=0.79 g/cm') d. 0.10 mole fraction of C,H12O6 in water (d=1.00 g/cm')
5. In lab, you need to prepare at least 100 mL of each of the following solutions. Explain how you would proceed using the given information. Like a lab manual, your answer should provide instructions in complete sentences, indicating specific masses, volumes, glassware, and equipment to be used. Your available chemicals include KCl(s), NAOH(s), C,H12O6(s), H2O(1), and CH;OH(1). a. 2.0 m KCl in water (density of H2O = 1.00 g/cm') b. 15% NaOH by mass in water (d = 1.00 g/cm') c. 25% NaOH by mass in CH3OH (d=0.79 g/cm') d. 0.10 mole fraction of C,H12O6 in water (d=1.00 g/cm')
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter4: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 101AE: You wish to prepare 1 L of a 0.02-M potassium iodate solution. You require that the final...
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Transcribed Image Text:5. In lab, you need to prepare at least 100 mL of each of the following solutions. Explain how you
would proceed using the given information. Like a lab manual, your answer should provide
instructions in complete sentences, indicating specific masses, volumes, glassware, and
equipment to be used. Your available chemicals include KCl(s), NaOH(s), C,H12O6(s), H2O(1),
and CH3OH(1).
2.0 m KCl in water (density of H2O = 1.00 g/cm')
b. 15% NaOH by mass in water (d = 1.00 g/cm')
25% NaOH by mass in CH3OH (d=0.79 g/cm')
d. 0.10 mole fraction of CH1206 in water (d=1.00 g/cm')
а.
С.
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