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- Given an integer n and an array a of length n, your task is to apply the following mutation to a: Array a mutates into a new array b of length n. For each i from 0 to n - 1, b[i] = a[i - 1] + a[i] + a[i + 1]. If some element in the sum a[i - 1] + a[i] + a[i + 1] does not exist, it should be set to 0. For example, b[0] should be equal to 0 + a[0] + a[1].Given an integer array nums and an integer val, remove all occurrences of val in nums in-place. The order of the elements may be changed. Then return the number of elements in nums which are not equal to val. Consider the number of elements in nums which are not equal to val be k, to get accepted, you need to do the following things: Change the array nums such that the first k elements of nums contain the elements which are not equal to val. The remaining elements of nums are not important as well as the size of nums. Return k. Example 1: Input: nums = [3,2,2,3], val = 3 Output: 2, nums = [2,2,_,_] Explanation: Your function should return k = 2, with the first two elements of nums being 2. It does not matter what you leave beyond the returned k (hence they are underscores). Example 2: Input: nums = [0,1,2,2,3,0,4,2], val = 2 Output: 5, nums = [0,1,4,0,3,_,_,_] Explanation: Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.…Given an array of integers arr, sort the array by performing a series of pancake flips. In one pancake flip we do the following steps: Choose an integer k where 1 <= k <= arr.length. Reverse the sub-array arr[0...k-1] (0-indexed). For example, if arr = [3,2,1,4] and we performed a pancake flip choosing k = 3, we reverse the sub-array [3,2,1], so arr = [1,2,3,4] after the pancake flip at k = 3. Print out the k-values corresponding to a sequence of pancake flips that sort arr. Example 1: Input: arr = [3,2,4,1] Output: 4, 2, 4, 3 Explanation: We perform 4 pancake flips, with k values 4, 2, 4, and 3. Starting state: arr = [3, 2, 4, 1]. After 1st flip (k = 4): arr = [1, 4, 2, 3] After 2nd flip (k = 2): arr = [4, 1, 2, 3] After 3rd flip (k = 4): arr = [3, 2, 1, 4] After 4th flip (k = 3): arr = [1, 2, 3, 4], which is sorted. Another potential solution is: Output = 3, 4, 2, 3, 1, 2, 1, 1 with a similar explanation. All potential solutions that solve the problem are…
- Given an array of locations in memory of n dimensions we want to find out what ordering it has in memory. For example, given the following input array [[[ 0 4 8 12] [16 20 24 28] [32 36 40 44]] [[48 52 56 60] [64 68 72 76] [80 84 88 92]]] your function has to return the tuple: [2,1,0] As a suggestion: - Loop through the number of dimensions - For each dimension generate a list of slices equivalent to the above indexing notation - Get the first two elements of each axis - Order the axes by the difference between those two elements Complete the code: def get_storage_order(r): import numpy as np return to check the code manually: r = np.array([[[ 0, 4, 8, 12], [32, 36, 40, 44], [64, 68, 72, 76]], [[16, 20, 24, 28], [48, 52, 56, 60], [80, 84, 88, 92]]]) get_storage_order(r)Given an array of locations in memory of n dimensions we want to find out what ordering it has in memory. For example, given the following input array [[[ 0 4 8 12] [16 20 24 28] [32 36 40 44]] [[48 52 56 60] [64 68 72 76] [80 84 88 92]]] your function has to return the tuple: [2,1,0] As a suggestion: - Loop through the number of dimensions - For each dimension generate a list of slices equivalent to the above indexing notation - Get the first two elements of each axis - Order the axes by the difference between those two elements Complete the code: def get_storage_order(r): import numpy as np returnPlease Help me with This Problem Language = C++ Take an array of name A of size 4 X 4. Take input and then take B with size 4 X 4. Add them.And show result after taking transpose.Formally, the i th row, j th column element of C T is the j th row, i th columnelement of C:1. write the rows of C as the columns of C T2. write the columns of C as the rows of C TC is an m × n matrix then C T is an n × m matrix.Then save the result in a file named “result.txt”, according the matrix spaces and newline. Note:Understand the Question Properly and Kindly Answer
- 1) Consider an integer array a of length n with indexing starting at 0, where n is a positive integer.If the elements of array a are to be written out in reverse order, which of the following C++ code fragment does NOT do the job? Question options: a. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} cout << a[i] << endl; b. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} c. int i=n-1; while (i>=0){cout << a[i] << endl; i = i-1;} d. int i=n; while (i>0){cout << a[i-1] << endl; i = i-1;} 2) Assume we use 8-bit cell to store floating point numbers, 1 bit for sign, 3 bits for excessed exponent, and 4 bits for significand. What is the decimal value for a cell with bit pattern 0 111 1101 Question options: a. 125 b. 224…Multiplying Factors For a pair of integers (x,y) and an integer k, the multiplying factor is defined as minimum positive integer m such that LCM(x,y) * m is divisible by k. Here LCM(x,y) represents the smallest positive integer divisible by both x and y, their least common multiple. Given an array arr of n integers and an integer k, find the sum of multiplying factors over all pairs of integers (arr[i], arr[j]) and k0 <= i,j < n. Example Suppose n=3, arr =[4,5,6] and k=12. Pair Multiplying Factor Remarks (4, 3 LCM(4,4)**3=4**3 =12 4 ) LCM(5,5)**12=5** 12=60 (5, 12 LCM(6,6)**2=6**2 5) (6, 2 12 6 )Let A be an array of numbers. In the maximum sub-array problem, your goal is to determine the sub-array A[x . . . y] of consecutive terms for which the sum of the entries is as large as possible. For example, if A = [−2, −3, 4, −1, −2, 1, 5, −3], the maximum sub-array is [4, −1, 2, 1, 5], and the largest possible sum is S = 4 − 1 − 2 + 1 + 5 = 7. Suppose A = [1, 2, −4, 8, 16, −32, 64, 128, −256, 512, 1024, −2048]. Determine S, the largest possible sum of a sub-array of A.
- Create an ABM function that takes the following parameters: n := number of paths to be simulated m := number of discretization points per path S0 := initial starting point dS=μdt+σdW Program the function by using two nested "for loops" def ABM(n,m,S0,mu,sigma,dt): np.random.seed(999) arr = # create 2D zeros array with the correct dimensions arr[,] = #initialize column 0 # fill in array entries for i in : for j in : arr[i,j] = return arr1. Consider a problem of computing the prefix average of a sequence of numbers stored in an array P consisting of P integers. We want to compute an array P such that P is the average of P for P . Consider the two algorithms related to the above problem. Answer the questions given belowWap Given a sorted array nums, remove the duplicates in-place such that each element appears only once and returns the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Clarification: Confused why the returned value is an integer but your answer is an array? Note that the input array is passed in by reference, which means a modification to the input array will be known to the caller as well. Internally you can think of this: // nums is passed in by reference. (i.e., without making a copy) int len = removeDuplicates(nums); // any modification to nums in your function would be known by the caller. // using the length returned by your function, it prints the first len elements. for (int i = 0; i < len; i++) { print(nums[i]); } Example 1: Input: nums = [1,1,2] Output: 2, nums = [1,2] Explanation: Your function should return length = 2, with the first two elements of nums being 1 and 2…