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Q: solve for the function, x^3- 0.03x^2+2.4x10^-6=0, assuming stopping criterion of es=0.1

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A: ∫028x7dx x=b-a2t+b+a2 change interval a,b=0,2into -1,1 using x=b-a2t+b+a2 a=0,b=2 x=t+1 t=x-1      d...

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