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5. The tank in Example 3.8 has a leak that admits air at the rate. 0.0005lbm (Poutside - Piank) min atm m How long does it take the pump to reduce the pressure in the tank from 1 atm to 0.01 atm? What is the steady-state pressure in the tank? Vacuum Sys 38

5. The tank in Example 3.8 has a leak that admits air at the rate. 0.0005lbm (Poutside - Piank) min atm m How long does it take the pump to reduce the pressure in the tank from 1 atm to 0.01 atm? What is the steady-state pressure in the tank? Vacuum Sys 38

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Plz help I am so lost I’m trying to solve for problem 5
5. The tank in Example 3.8 has a leak that admits air at the rate. 0.0005lbm min-atm Mass balance equation dm dt How long does it take the pump to reduce the pressure in the tank from 1 atm to 0.01 atm? What is the steady-state pressure in the tank? V = 10ft³ T = 68°F Vacuum Sys 3.8 LOFE Leak min sys = -mout + min const Voys desys dt == M LEA Qout esys In esys, Final - esys, initial Do we set A=∞ Poutside desys [esys - (min/ Qout) min Qout (min esys, Final = Qout min Qout Plank 3 Vol = + min at 68°F = 20°C 68°P HEATER or At= Qout Vsys Cair Psteady state = 1 atm Temp Cont Vsys Qout de Qout Vsys Valuum pussy In At esys initial esys Final 0.075 1bm m/ft 3 esys final -?? 0.0751bm/ft
Transcribed Image Text:5. The tank in Example 3.8 has a leak that admits air at the rate. 0.0005lbm min-atm Mass balance equation dm dt How long does it take the pump to reduce the pressure in the tank from 1 atm to 0.01 atm? What is the steady-state pressure in the tank? V = 10ft³ T = 68°F Vacuum Sys 3.8 LOFE Leak min sys = -mout + min const Voys desys dt == M LEA Qout esys In esys, Final - esys, initial Do we set A=∞ Poutside desys [esys - (min/ Qout) min Qout (min esys, Final = Qout min Qout Plank 3 Vol = + min at 68°F = 20°C 68°P HEATER or At= Qout Vsys Cair Psteady state = 1 atm Temp Cont Vsys Qout de Qout Vsys Valuum pussy In At esys initial esys Final 0.075 1bm m/ft 3 esys final -?? 0.0751bm/ft
contains air, The microchip diffusion furnace in Fig. which may be considered an ideal gas. The vacuum pump is pumping air out prior to beginning the thermal diffusion step. During the pumpout process the heating coils in the tank hold the temperature in the tank constant at 68°F. The volumetric flow rate at the inlet of the pump, independent of pressure, is 1.0 ft³/min. Volume 10 ft³ 68°F Heater Vacuum pump diffusion furnac Temperature controller Evacuation of a microchip
Transcribed Image Text:contains air, The microchip diffusion furnace in Fig. which may be considered an ideal gas. The vacuum pump is pumping air out prior to beginning the thermal diffusion step. During the pumpout process the heating coils in the tank hold the temperature in the tank constant at 68°F. The volumetric flow rate at the inlet of the pump, independent of pressure, is 1.0 ft³/min. Volume 10 ft³ 68°F Heater Vacuum pump diffusion furnac Temperature controller Evacuation of a microchip
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