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5.164 20-4f 11₁₂=14001 pm a) If= 1.2.4 C 193 R₁=15-2 P=5KIJ-Pack

5.164 20-4f 11₁₂=14001 pm a) If= 1.2.4 C 193 R₁=15-2 P=5KIJ-Pack

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter21: Resistive-capacitive Series Circuits
Section: Chapter Questions
Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...
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Hello my friend, just rewrite the question on the computer in digital form, not handwriting + also drawing the electrical circuit
15.164--2p=44 Rs.82 11₁ = 14001 prs (a) If= 1.24 from figure (2) by intersect the value of If=1₁2 to find the Eart 1² Fo=300TT at Mompre R₁=15-2 P₁²=5KWU=Punk Ifel-by 15 JA-18-257A CONFO Port = I² R₂ II- 12- 5000-333-333 تكابها AIf = If I f ATF= 12-1·03-0·17 A 155 VA-EA-JARA V₁ Since VA TAR₁ = 18-257+15=273-5557² 273-855-E₁ 18 257×0.8 1.5 at 1400 rpm SE-EEA tond -360-25796=10₂04³5 from fignre (2) by intersect the value of EA= 289 961² with Curre to Curve to find I'fa T'p - 103A W/
Transcribed Image Text:15.164--2p=44 Rs.82 11₁ = 14001 prs (a) If= 1.24 from figure (2) by intersect the value of If=1₁2 to find the Eart 1² Fo=300TT at Mompre R₁=15-2 P₁²=5KWU=Punk Ifel-by 15 JA-18-257A CONFO Port = I² R₂ II- 12- 5000-333-333 تكابها AIf = If I f ATF= 12-1·03-0·17 A 155 VA-EA-JARA V₁ Since VA TAR₁ = 18-257+15=273-5557² 273-855-E₁ 18 257×0.8 1.5 at 1400 rpm SE-EEA tond -360-25796=10₂04³5 from fignre (2) by intersect the value of EA= 289 961² with Curre to Curve to find I'fa T'p - 103A W/
b) а2=1000крас Чассаттарань IN-15A -220=EA+ 1500-8 +1.5 EA₂ 206-5 V at 1000rpm +7 220V I C²T = EA TA 271 Tot 206 5% 15 =BA Shurit EAT - (1₁/1_) EAT (14.00/1000/206-5=289-1 V at 14ocipe from figure (2) by Intersect the Vstus of EA with Curve to find Ife 20 J j = 1.025A DE 005 EA AF÷Eo-EA effective Es = 289+1+0+5*289-1=303-555 V by intersect this liatue of to with Curve in figure (2) to find the actual valuy of current field. • If= 1.245 A actual I = If+ ŢA = 1245+15=16-245A Tot = 206-5+15 = 29.579///.m 271icco wront
Transcribed Image Text:b) а2=1000крас Чассаттарань IN-15A -220=EA+ 1500-8 +1.5 EA₂ 206-5 V at 1000rpm +7 220V I C²T = EA TA 271 Tot 206 5% 15 =BA Shurit EAT - (1₁/1_) EAT (14.00/1000/206-5=289-1 V at 14ocipe from figure (2) by Intersect the Vstus of EA with Curve to find Ife 20 J j = 1.025A DE 005 EA AF÷Eo-EA effective Es = 289+1+0+5*289-1=303-555 V by intersect this liatue of to with Curve in figure (2) to find the actual valuy of current field. • If= 1.245 A actual I = If+ ŢA = 1245+15=16-245A Tot = 206-5+15 = 29.579///.m 271icco wront
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