5.3. The yield of a chemical process is being studied. The two most important variables are thought to be the pressure and the temperature. Three levels of each factor are selected, and a factorial experiment with two replicates is performed. The yield data are as follows: Pressure (psig) Temperature (°C) 200 215 230 150 90.4 90.7 90.2 90.2 90.6 90.4 160 90.1 90.5 89.9 90.3 90.6 90.1 170 90.5 90.8 90.4 90.7 90.9 90.1 Analyze the data and draw conclusions. Use a= 0.05
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- A research group is interested in the relationship between exposure to mold in households after a major hurricane and the onset of acute respiratory illness in children. Suppose an observational study is conducted over 10 years following the natural disaster and the following two-by-two table was created in order to address the relationship between exposure and outcome. Acute Respiratory Illness No Acute Respiratory Illness Total Mold 378 156 534 No Mold 73 260 333 Total 451 416 867 Calculate the incidence of acute respiratory illness in the exposed and unexposed. Calculate the relative risk for ARI due to exposure in this study Interpret your findings from part BLife-saving drug: Penicillin is produced by the Penicillin fungus, which is grown in a broth whose sugar content must be carefully controlled. Several samples of broth were taken on three successive days, and the amount of dissolved sugars, in milligrams per milliliter, was measured on each sample. The results were as follows. Day 1: 5.2 5.0 5.4 5.2 5.3 5.0 4.9 5.0 5.2 5.0 4.6 5.3 Day 2: 5.6 4.8 4.9 5.3 5.2 4.9 5.4 5.0 5.4 4.9 5.5 5.4 Day 3: 5.9 4.9 5.3 5.4 5.2 5.5 5.0 5.8 5.5 5.4 5.4 5.1 Construct an ANOVA table. Round your answers to four decimal places as needed. One-way ANOVA: Sugar Concentration Source DF SS MS F P Days Error TotalPenicillin is produced by the Penicillin fungus, which is grown in a broth whose sugar content must be carefully controlled. Several samples of broth were taken on three successive days, and the amount of dissolved sugars, in milligrams per milliliter, was measured on each sample. The results were as follows. Day 1 : 4.9 5.4 5.3 4.9 5.2 5.1 5.4 4.9 5.1 5.1 4.9 5.4 Day 2 : 5.5 5.2 5.1 5.0 5.3 5.4 5.3 5.2 5.4 5.3 5.4 5.1 Day 3 : 5.8 5.0 5.4 5.5 5.5 5.5 4.8 5.5 5.2 4.9 5.5 5.0 Construct an ANOVA table. Round your answers to four decimal places as needed. One-way ANOVA: Sugar Concentration Source DF SS MS F P Days Error Total Is there enough evidence to conclude that the mean sugar concentration…
- A study was undertaken to determine whether there was a significant weight (in lb) loss after one year course of therapy for diabetes, and whether the amount of weight (in lb) loss was related to initial weight. The following table gives the initial weight (x) and weight after one year of therapy (y) for 16 newly diagnosed adult diabetic patients.Recent publications have addressed the growing concern in the scientific community around the increased prevalence of CAT scans in children between the ages of 7-18 and the growing rate of childhood cancers. Suppose the researcher plans to gather a SRS from a group of children in this age range who have received one or more CAT scans, and a SRS from a group of children who have never received a CAT scan and compare the number of cases of childhood cancers that develop over a prolonged period of time. Assume the following table summarizes the descriptive statistics for his samples. Population Average cases of childhood cancers Standard deviaton Sample size >CAT scan 24.6 2.4 1,894 No CAT scans 11.4 1.9 2,745 A) Carry out the appropriate statistical test to answer the researcher’s hypothesis regarding the difference in average cases of childhood cancers in children aged 7-18 receiving one or more CAT scans versus those that have never received a CAT scan. Use an alpha level…Consider a cohort study to compare the mortality rate of myocardial infarction (MI) in men with sedentary work (exposed group) to men with physically active work (unexposed). If in the exposed, there were 36,000 person (man) years of observation and 126 deaths whereas the unexposed had 24,000 man-years of observation and 44 deaths. Compute the following a) Mortality rate in each cohort? b) What is the relative risk of dying, comparing these 2 groups? c) What is the attributable risk of sedentary work? d) What is the attributable benefit of physical activity? e) If we assume that MI is associated with the mortality in this cohort (causality), what proportion of the disease in the higher group is potentially preventable?
- Is there a significant difference between the population means of group 1 and group 2 kindergarten children on a social perceptiveness measures at 0.05 level? Consider the data below Group 1 Group 2Mean 21.3 18.1Sd 5.8 7.5N 15 10Q1 A) List down the measures of central tendency and measures of dispersion 2) The operations manager of a plant that manufactures tires wants to compare the actual inner diameters of two grades of tires, each of B) which is expected to be 575 millimeters. A sample of five tires of each grade was selected, and the results representing the inner diameters of the tires, ranked from smallest to largest, are as follows. Grade X grade Y 568 570 575 578 584 573 574 575 577 578 requirement. a) for each of the tow grades of tries, compute the mwan, median, and standred deviation. b) which grade of tire providing better quality? explain. c) what would be the effect on your answer in (a) and (b) if the last value for grade Y were 588 insert 578 explain. C) The file contins the overall miles per gallon (MPG) OF 2010 family sedan: 24 21 22 23 24 34 34 34 20 20 22 22 44 32 20 20 22 20 39 20 Source:…Blood cocaine concentration (mg/L) was determinedboth for a sample of individuals who had died fromcocaine-induced excited delirium (ED) and for a sampleof those who had died from a cocaine overdose withoutexcited delirium; survival time for people in bothgroups was at most 6 hours. The accompanying datawas read from a comparative boxplot in the article“Fatal Excited Delirium Following Cocaine Use” (J.of Forensic Sciences, 1997: 25–31). ED 0 0 0 0 .1 .1 .1 .1 .2 .2 .3 .3.3 .4 .5 .7 .8 1.0 1.5 2.7 2.83.5 4.0 8.9 9.2 11.7 21.0Non-ED 0 0 0 0 0 .1 .1 .1 .1 .2 .2 .2.3 .3 .3 .4 .5 .5 .6 .8 .9 1.01.2 1.4 1.5 1.7 2.0 3.2 3.5 4.14.3 4.8 5.0 5.6 5.9 6.0 6.4 7.98.3 8.7 9.1 9.6 9.9 11.0 11.512.2 12.7 14.0 16.6 17.8 a. Determine the medians, fourths, and fourth spreadsfor the two samples.b. Are there any outliers in either sample? Any extremeoutliers?c. Construct a comparative boxplot, and use it as abasis for comparing and contrasting the ED andnon-ED samples.
- A deficiency of the trace element selenium in the diet can negatively impact growth, immunity, muscle and neuromuscular function, and fertility. The introduction of selenium supplements to dairy cows is justified when pastures have low selenium levels. Authors of a research paper supplied the following data on milk selenium concentration (mg/L) for a sample of cows given a selenium supplement (the treatment group) and a control sample given no supplement, both initially and after a 9-day period. Initial Measurement Treatment Control 11.2 9.1 9.6 8.7 10.1 9.7 8.5 10.8 10.3 10.9 10.6 10.6 11.7 10.1 9.7 12.3 10.8 8.8 10.3 10.4 10.4 10.9 11.2 10.4 9.4 11.6 10.6 10.9 10.7 8.4 After 9 Days Treatment Control 138.3 9.3 104 8.7 96.4 8.7 89 10.1 88 9.6 103.8 8.6 147.3 10.2 97.1 12.2 172.6 9.3 146.3 9.5 99 8.2 122.3 8.9 103 12.5 117.8 9.1 121.5 93 (a) Use the given data for the treatment group to determine if there…A deficiency of the trace element selenium in the diet can negatively impact growth, immunity, muscle and neuromuscular function, and fertility. The introduction of selenium supplements to dairy cows is justified when pastures have low selenium levels. Authors of a research paper supplied the following data on milk selenium concentration (mg/L) for a sample of cows given a selenium supplement (the treatment group) and a control sample given no supplement, both initially and after a 9-day period. Initial Measurement Treatment Control 11.3 9.1 9.7 8.7 10.1 9.7 8.5 10.8 10.4 10.9 10.7 10.6 11.8 10.1 9.8 12.3 10.6 8.8 10.4 10.4 10.2 10.9 11.3 10.4 9.2 11.6 10.7 10.9 10.8 8.2 After 9 Days Treatment Control 138.3 9.4 104 8.8 96.4 8.8 89 10.1 88 9.7 103.8 8.7 147.3 10.3 97.1 12.3 172.6 9.4 146.3 9.5 99 8.3 122.3 8.9 103 12.5 117.8 9.1 121.5 93 (a) Use the given data for the treatment group to determine if…