(5.9: Similar to Example 5.14) Use oxidation states to identify the element that is oxidized and the element that is reduced in the reaction below. 2 Li(s) + Cl₂(g) --> 2 LiCl(s) oxidized element [Choose ] [Choose] Li reduced element CI No oxidized element exists. No reduced element exists.

(5.9: Similar to Example 5.14) Use oxidation states to identify the element that is oxidized and the element that is reduced in the reaction below. 2 Li(s) + Cl₂(g) --> 2 LiCl(s) oxidized element [Choose ] [Choose] Li reduced element CI No oxidized element exists. No reduced element exists.

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter18: Electrochemistry

Section: Chapter Questions

Problem 18.92QE

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

(5.9: Similar to Example 5.14) Use oxidation states to identify the element that is oxidized and the element that is reduced in the
reaction below.
2 Li(s) + Cl₂(g) --> 2 LiCl(s)
oxidized element
[Choose ]
[Choose]
Li
reduced element
CI
No oxidized element exists.
No reduced element exists.

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