(-5,0) (5,0x Form the fourth-degree polynomial function with real coefficients sketched here given that -1+3i is a zero. (1,-1248 f(x) - (Simplify your answer. Use integers or fractions for any numbers in the expression. Type an expression using x as the variable.)

Q: Find the polynomial function f with real coefficients that has the given degree, zeros, and solution…

A: This question is based on roots of a function.

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A: We Find the Polynomial Function F (x)of degree 3 that has the Following Zeros          5, 1, -6

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A: Given Data: The degree of the function is: 4 The zeros of the functions are: -4, 1, i The solution…

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A: Topic: polynomial function

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A: Zeroes always exist in conjugate pairs for imaginary numbers. So conjugate of -i is i and conjugate…

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Q: Degree: 3 Roots: x=2, x=-4

A: given: Degree: 3 , Roots: x=2, x=-4 Since the degree is 3 and we have only two roots, one has to be…

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A: To find a polynomial function

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A: GIVEN: Degree : 3 zeroes : -7, 1 + 3i solution points f(-2) = 60

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A:

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A: Let the function be fx=ax3+bx2+cx+d It is given that f-1=50, ⇒f-1=a-13+b-12+c-1+d50=-a+b-c+d…………i…

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A: Given that, .........(1) ..........  (2) We take a=3 Hence equation (1) and (2)  becomes,

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A: Put value in polynomial equation

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A: we have given n=3 and 3 and 4i are the roots of polynomial and f(1)=34if we take polynomial with…

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A: We have to find

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A: Polynomial function with degree 3 is f(x) = p(x-a)(x-b)(x-c) Where a,b and c are zeros of function.

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A: Explained below

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A: Given Zeroes are x=-4i   and x=8 x+4ix-8=0 x2-8x+i4x-32i=0 x2+(4i-8)x-32i=0

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A: For this problem, first we need to write in factored form.

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A: 31) The degree of the polynomial function is 6 and the dominant term is =2*x*x^3*x*4*x=8x^6

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Roots

The main dissimilarity between real and complex roots is that the real roots are obtained as real numbers, in contrast with the complex roots, which are indicated as imaginary numbers. The standard format for depicting any complex number is in the form of a + bi.