50 cm 10 cm 8.0 A R = 1.0 x 10-3 2 A small circular loop of wire of radius 5 cm and resistance 1E-3 Q is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter27: Current And Resistance
Section: Chapter Questions
Problem 27.65AP
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50 cm
10 cm
8.0 A
R = 1.0 × 10-3 N
A small circular loop of wire of radius 5 cm and
resistance 1E-3 Q is centered inside a large circular
loop of wire of radius 50 cm. The larger loop, which
initially carries a current of 8 A, is cut and its current
is reduced to zero over a time interval of 1E-6 s. Our
goal will be to find the average current in the smaller
loop during this time interval. (The magnetic field of
the larger loop is approximately constant over the
smaller loop.)
Transcribed Image Text:Instructions 50 cm 10 cm 8.0 A R = 1.0 × 10-3 N A small circular loop of wire of radius 5 cm and resistance 1E-3 Q is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)
Magnitude of the magnetic field
B within the small loop:
O 3.2E-6 T
O 3.2E-8 T
O 1.0E-5 T
O 1.0E-7 T
Transcribed Image Text:Magnitude of the magnetic field B within the small loop: O 3.2E-6 T O 3.2E-8 T O 1.0E-5 T O 1.0E-7 T
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