500 kN 300 kN 100 mm 100 mm 100 mso mm 50 mim 150 mm 150 mm 150 mm

Q: 200 mm 150 mm 100 mm 200 mm

A:

Q: Find the force generated by pliers on piece DC 5N C 70mm 40mm 5N Select one: O a. 8.75 N O b. 5N OC.…

A:

Q: 90mm 60mm 45mm R15mm

A: Let’s divide the given section into 3 sections. Section 1 is a rectangular OABC. Section 2 is the…

Q: -3t 4.8. x(t) = -4.132 x 10-2e sin(29.85t – 1.5529) +9.820 x 10-3 sin(15t – 0.1343) |

A:

Q: Match the allowance and limit parameter in

A: Given data; Column given below; Column 1= Allowance and limit paramater Column 2=Quantitative…

Q: Given the following duty record, how much life is consumed at each stress level? 60 ksi 49 ksi 10…

A: An S-N curve establishes the number of cycles required to cause failure when a material is…

Q: Q.06 A ircula hole of20 m diameteris to e poduce inashe of mm thckes.The lerance allowance between…

A: Given: Hole diameter, d = 20 mm Sheet thickness, t = 4 mm Clearance allowance= 3 %

Q: Impact strength value increases with increase in cross-sectional area at notch. Select one: True…

A: Impact Strength : it is defined as the ratio of Energy absorbed upto fracture point to the Area of…

Q: 30o0mm*300 mmXJ0omm

A: Given data :- 300mm × 300mm × 300mm  Compare L × b × h  Here L= length           b= width…

Q: 3T Aluminum Steel 75 mm Bronze 100 mm 5m t- 3m 2m

A: For solution refer below images.

Q: 250 mm K3 rad/S 300 300 mm 400 mm

A: AS PER THE POLICY OF THE COMPANY, ONLY FIRST 3 SUBPARTS WILL BE ANSWERED. KINDLY POST REST OF THE…

Q: An eyebolt is lifting a block weighing 360 lbs. The eyebolt is of SAE 1040 material with Su = 67 ksi…

A: Given data Weight of block = 360 lb Sy = 55 ksi = 55000 lb/in2 We have to find the stress area of…

Q: 2. what is the reduction ratio, if D.-94mm, this means r=47mm=0.047m If pressure (P) = 45Mpa (45*106…

A: given data  initial diameter = 94 mm final diameter = 16 mm pressure = 45 Mpa.

Q: ust be from the origin. 70 mm mm 60 mm 10 mm

A: Area symbol area mm2 x̄(mm) ȳ (mm) A x̄(mm3) A ȳ (mm3) A1 40*15=600 -62.5 27.5 -37500…

Q: Question No.15: Write briefly about fits and tolerances used in design. And solve this example: A…

A: Given; Fits and tolerances, Dmin= 50 mm Hole tolerances=0.025 mm

Q: 200 mm Gmm -4mm 400 8mm 102mm

A:

Q: 2.000 2.500 000'9 000 000 0007 RO.500

A: CNC PROGRAM G99  G21 G40 S1000 M13 M06 T0101 G00 X5.5 Z0.25 G01 X5 Z0 F0.005 G71 P10 Q20 U0.01…

Q: -150 mm 15 mm B C 150 mm -15 mm 15 mm - 100 mm·

A: given;

Q: elect the diameter of the cylinder to be used from L=150mm, if it is required to apply a force of…

A: Given   Pressure, P = 80 psi                     = 551.58 kPa       Mass, m = 350 kg Find…

Q: w = 35 kN/m 38-mm diameter 38-mm diameter 150-mm diameter 100 mm 300 mm 100 mm

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Q: 10 mm Y 15 mm 30 mm 40 mm 10 mm 15 mm X

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Q: Draw shear force and bending momenE

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Q: - 100 mm 20 mm yo 140 mm -20 mm 20 mm - 100 mm

A: Rectangle Area (mm2) x¯ (in) y¯ (in) x¯y¯A (in4) I 2000 -50 70 -7000000 II 2400 0 0 0 III 2000…

Q: 100 mm 100 mm 10 mm 10 mm. 200 mm 100 mm f 10 mm I II

A: For the selection of sections, we have to calculate the maximum bending stress in the beam. From the…

Q: 19. What is the equivalent torsional stiffness of the shafts in Fig.15? 2k 3k Fig. 15

A: Since we only answer one question at a time, we will answer the first one. Please resubmit the…

Q: 150 mm 50 mm 200 mm 50 mm 30 mm 200 mm -50 mm

A:

Q: The length, width and thickness of a steel sar Its thickness needs to be uniformly reduced milling.…

A: GivenD=100mmw=50mmz=20toothN=1200rpmft=0.05mm/tooth revf=z×ftf=20×0.05f=1mm/rev

Q: 1. A shaft made of steel having an ultimate strength of Su is finished by grinding the surface. The…

A:

Q: Define the various types of fits? Also define fits in terms of shaft and hole basis system

A: Fits is defined as a term that is widely used in manufacturing engineering. It is the assembly…

Q: 6 mm 55 mm 10 mm

A: Impact loads are those loads that are acting for a short span of time. Toughness is defined as the…

Q: a) 10mm IG mm IG mm 1050mm IG mm 16mm 250 mm 300 mm

A:

Q: cement: FLDE mm CF mm mm 1 1.5 84 = 8p + 8c = mm tan a = α Ans 1500 FALAH = A/H mm AH 8 = 8g +84H mm…

A:

Q: Locate the centroid of the plane area shown.

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 100 mm 30 50 mm

A:

Q: -r = 100 mm 50 mm -180 mm

A: As per our guidelines, experts can provide solution to only one problem in case of multiple…

Q: What is the diameter of line shaft that transmit 180 kW at 25 rps?

A:

Q: В 125 mm A 175 mm C OD - 225 mm 150 N 75 mm

A:

Q: The following limits are specified in a limit system, to give a clearance fit between a hole and a…

A: basic size of hole and shaft is 25mm Hole: maximum limit of hole = 25+0.03 =25.03mm minimum limit of…

Q: A -A, = 660 mm 2m Cap plate 3m Anc =860 mm

A: Given:AAB=660 mm2ABC=860 mm2E=110 GPaNote: According to Bartleyby's policy we shall answer only…

Q: A copper tube with wall thickness of 8 mm must carry an axial tensile force of 175 kN. The allowable…

A:

Q: A petrol engine has a cylinder diameter and stroke of 120mm and 235 mm respectively. The clearance…

A: Given: Diameter of cylinder , D = 120 mm = 0.12 m Length of stroke , L = 235 mm = 0.235 m  Clearance…

Q: - R60mm Fig 10 100mm 20hm 20mm 100mm 40mm pun ser

A: For a composite area consisting of many areas Ai, each with centroid at locations xi¯,yi¯, the…

Q: 300, lb 300 lb 800, lb 300, lb 800, lb 9 ft G B C D E F 700 Ib. 700 lb 6 panels e 5 rt/panet

A: GIVEN DATA - Truss Given   We have to find force in given member using method of joint

Q: 13 in. 11 in. 7 in. 140 D 4 in. ES

A: Consider the member BE, Balancing horizontal force,HB+HD+25=0Takng moment about…

Q: 2400 mm C 1200 mm 1200 mm 1200 mm 2400 mm

A: The free-body diagram of the plate is shown as, Given, m=102.1 kgW=102.1×9.81=1000.58 N

Q: A petrol engine has a cylinder diameter and stroke of 120mm and 245 mm respectively. The clearance…

A: Given data: The diameter of the cylinder is, d=120 mm=120 mm×1 m1000 mm=0.12 m. The stroke of the…

Q: 30mm diameter copper (G-4S GPa) shaft is transmitting power at 1000 rpm. The twisting angle should…

A:

Q: Determine the diameter of a main power transmitting shaft in mm to transmit 114 kW at 430 rpm using…

A: Assuming shear stress t=to be = 27.58 MPa = 4000 psi ( PSME shaft code for head shaft) Power =…

Q: REVISION HSTORY DATE NOTES: 140mm 180mm 16mm 1 20mm R18mm RIomm- 164mm -20mm 10mm PARTS LIST INIT…

A: It is given that all the dimensions are shown in top view and front view. So by helping these…

Buckling of columns

The column is described as a vertical member of the structure that carries an axial compressive load, and buckling is a lateral deformation of the column under the application of load.