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58. y = x³ - 24 ln x, [2,3]

58. y = x³ - 24 ln x, [2,3]

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Number 58
In Exercises 29–58, find the minimum and maximum value of the func- tion on the given interval by comparing values at the critical points and endpoints.
Transcribed Image Text:In Exercises 29–58, find the minimum and maximum value of the func- tion on the given interval by comparing values at the critical points and endpoints.
39. = x² +1 X- - 4 41. y = x - 4x x+1 55. y = [5,6] X 9 42. y = 2√√x² +1−x, [0, 2] 43. y = (2 + x)√√2+ (2 − x)², [0, 2] 44. y = √1+x²–2x, [0, 1] [0, 4] 45. y = √√√x + x²-2√x, 47. y sin x cos x, [0, 1] 49. y = √20 sec 0, [0, 1] 50. y = cos 0 + sin 0, [0, 2л] X [0, 3] 51. y = 0 - 2 sin 0, [0, 2π] 52. y = 4 sin³ 0 - 3 cos²0, [0, 2π] 53. y = tan x-2x, [0, 1] ln x [1, 3] 40. y 57. y = 3ete²x, [−1,¹] = 1- x x² + 3x² [1,4] 46. y = (t t²)1/3, [1,2] 48. y = x + sinx, [0, 2π] 54. y = xe-*, [0, 2] 56. y = 5 tan 58. y = x³ - 24 ln x, -1 x -x, [1, 5] [1/2,3]
Transcribed Image Text:39. = x² +1 X- - 4 41. y = x - 4x x+1 55. y = [5,6] X 9 42. y = 2√√x² +1−x, [0, 2] 43. y = (2 + x)√√2+ (2 − x)², [0, 2] 44. y = √1+x²–2x, [0, 1] [0, 4] 45. y = √√√x + x²-2√x, 47. y sin x cos x, [0, 1] 49. y = √20 sec 0, [0, 1] 50. y = cos 0 + sin 0, [0, 2л] X [0, 3] 51. y = 0 - 2 sin 0, [0, 2π] 52. y = 4 sin³ 0 - 3 cos²0, [0, 2π] 53. y = tan x-2x, [0, 1] ln x [1, 3] 40. y 57. y = 3ete²x, [−1,¹] = 1- x x² + 3x² [1,4] 46. y = (t t²)1/3, [1,2] 48. y = x + sinx, [0, 2π] 54. y = xe-*, [0, 2] 56. y = 5 tan 58. y = x³ - 24 ln x, -1 x -x, [1, 5] [1/2,3]
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