5х -4 f(x) = 6x2 + 7x- 3 Part 1 of 3 5х -4 f(x) = will not be a real number when the denominator is zero. 6x + 7x- 3 Part: 1/3 Part 2 of 3 fhat is, when 6x2 + 7x – 3 = 0 OO = 0 x = and x =

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.9: Dividing Real Numbers
Problem 10MRE
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5х-4
f (x) =
6x + 7x- 3
Part 1 of 3
5x -4
f(x)
will not be a real number when the (denominator
is zero.
6x +7x-3
Part: 1/3
Part 2 of 3
fhat is, when
6x² + 7x -3 = 0
00 =0
X =
and x =
Transcribed Image Text:5х-4 f (x) = 6x + 7x- 3 Part 1 of 3 5x -4 f(x) will not be a real number when the (denominator is zero. 6x +7x-3 Part: 1/3 Part 2 of 3 fhat is, when 6x² + 7x -3 = 0 00 =0 X = and x =
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