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6 + (-3) + 0 + ..+ 411 = 97 (a* + 5) - 0 k = 1

6 + (-3) + 0 + ..+ 411 = 97 (a* + 5) - 0 k = 1

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.1: Sequences And Series
Problem 6ECP: Write the first five terms of the sequence given by an=3n+1n!. Begin with n=0.
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Compute the sums below. (Assume that the terms in the first sum are consecutive terms of an arithmetic sequence.) -6 + (-3) + 0 + . .. + 411 = 97 (4* + 5) = 0 %3D k = 1
Transcribed Image Text:Compute the sums below. (Assume that the terms in the first sum are consecutive terms of an arithmetic sequence.) -6 + (-3) + 0 + . .. + 411 = 97 (4* + 5) = 0 %3D k = 1
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