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64210x(m)923610-2-4-6EN(N)

Question

The graph shows the force acting on an object as a function of the position of the object. For each numbered interval given, find the work ??Wi done on the object. 1) from ?=0 mx=0 m to ?=2.90 m. 2) from ?=3.00 mx=3.00 m to ?=6.50 m. 3) from ?=7.00 mx=7.00 m to ?=9.50 m.

6
4
2
10
x(m)
9
2
3
6
10
-2
-4
-6
EN
(N)
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6 4 2 10 x(m) 9 2 3 6 10 -2 -4 -6 EN (N)

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Step 1
  1. a) Work done is,
W = Fd
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W = Fd

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Step 2

Area under the Force-displacement graph will give the work done. Area from x=0 m to x=2.9 m is divided into three sections. First region is from x=0 m to x=1 m, second one is from x=1 m to x=2 m and third section is from x=2 m to x=2.9 m. Area or work done is,

-[(2NIm)] (2N)(Im)4N(m)[(6N).9m)]
2N .m+4N m11.4N-m
=17.4N.m
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-[(2NIm)] (2N)(Im)4N(m)[(6N).9m)] 2N .m+4N m11.4N-m =17.4N.m

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Step 3

Answer:17.4...

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Work,Power and Energy

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