(6) 6.z = -tResolute Rebecca believes she is limitless moving forward along herpath! Determine if she is right by finding the limit as she approachest = 0 on her position curve defined by r(t)=t²i+3tj+1-costkt r11eT(8) 7. a) Sketch the curve traced out by r(t) = (3 cost, 2 sint, -2)XTCb) Sketch the position vector and tangent vector to the curve at t == 2ZyReckless Rebecca decides to take up skydiving and jump from anacrobatic plane flying along the path given by r(t) = (4t,3,3t²)She chickens out and plans to jump when the path's curvature is 0.How long after take-off does she jump?(8) 8.

Answered: Image /qna-images/answer/81be042b-4834-4211-8ac7-94e1ab8b6fd5.jpg

(6) 6. 1 y z = -t Resolute Rebecca believes she is limitless moving forward along her path! Determine if she is right by finding the limit as she approaches 1 = 0 on her position curve defined by r(t) = f²i+3tj+(¹ -cost t

(6) 6. 1 y z = -t Resolute Rebecca believes she is limitless moving forward along her path! Determine if she is right by finding the limit as she approaches 1 = 0 on her position curve defined by r(t) = f²i+3tj+(¹ -cost t

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter1: Functions

Section1.2: Functions Given By Tables

Problem 32SBE: Does a Limiting Value Occur? A rocket ship is flying away from Earth at a constant velocity, and it...

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Question

(6) 6.
z = -t
Resolute Rebecca believes she is limitless moving forward along her
path! Determine if she is right by finding the limit as she approaches
t = 0 on her position curve defined by r(t)=t²i+3tj+
1-cost
k
t

r
11
e
T
(8) 7. a) Sketch the curve traced out by r(t) = (3 cost, 2 sint, -2)
X
TC
b) Sketch the position vector and tangent vector to the curve at t == 2
Z
y
Reckless Rebecca decides to take up skydiving and jump from an
acrobatic plane flying along the path given by r(t) = (4t,3,3t²)
She chickens out and plans to jump when the path's curvature is 0.
How long after take-off does she jump?
(8) 8.

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