(6 kg) block rests on a smooth table. It is connected by a string of negligible mass to a (2 kg) block hanging over the end of the table, as shown in figure below. Find: (&) The acceleration of each block? Answer : (a=2.45 m/s*) (b) The tension in the connecting string? Answer: (T=147N) (@) The position of mass A at (0.400 s)? Answer: (y=-0.196 m) (d) The velocity of mass A at (0.400 s)? Answer : (v=-0.980 m/s )

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter5: Newton's Law Of Motion
Section: Chapter Questions
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A (6 kg) block rests on a smooth table. It is connected by a string of negligible mass to a (2 kg) block hanging over the end of the table, as shown in figure below. Find: (&) The acceleration of each block? Answer : (a=2.45 m/s*) (b) The tension in the connecting string? Answer: (T=147N) (@) The position of mass A at (0.400 s)? Answer: (y=-0.196 m) (d) The velocity of mass A at (0.400 s)? Answer : (v=-0.980 m/s )
Problem 1.36
Combined motion of a block moving on a smooth
horizontal surface and a mass falling vertically
A (6 kg) block rests on a smooth table. It is connected by
a string of negligible mass to a (2 kg) block hanging over the
end of the table, as shown in figure below. Find:
(a) The acceleration of each block?
Answer : (a = 2.45 m/s* )
(b) The tension in the connecting string?
Answer : (T = 14.7 N)
(e) The position of mass A at (0.400 s)?
Answer : (y = - 0.196 m )
(d) The velocity of mass A at (0.400 s)?
Answer : (v = - 0.980 m/s )
me- 6 kg
MA-2 kg
Transcribed Image Text:Problem 1.36 Combined motion of a block moving on a smooth horizontal surface and a mass falling vertically A (6 kg) block rests on a smooth table. It is connected by a string of negligible mass to a (2 kg) block hanging over the end of the table, as shown in figure below. Find: (a) The acceleration of each block? Answer : (a = 2.45 m/s* ) (b) The tension in the connecting string? Answer : (T = 14.7 N) (e) The position of mass A at (0.400 s)? Answer : (y = - 0.196 m ) (d) The velocity of mass A at (0.400 s)? Answer : (v = - 0.980 m/s ) me- 6 kg MA-2 kg
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