6) Which of the following statement(s) is/are correct? i. The ratio of the test temperature to the melting point is known as homologous temperature. ii. Testing at high temperature accentuates superplastic behavior. iii. Testing at high strain rate accentuates superplastic behavior. i and iii Only ii and iii Only i and ii only i, ii and iii
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- 3 l Two tensile samples were cut from a titanium ingot that was cooled very slowly, and under specific conditions so that the ingot was a single crystal. The samples were then put in a tensile tester to determine their 0.2% offset σys. The σys for the two samples resulted in one sample having a value that was twice of the other. What could the cause be?Select All the correct statements from below. a. If the averaged distance between partial dislocations for material A observed under TEM is smaller than material B, the estimated stacking fault energy of material A is lower than material B. b. K_IC is a material property that doesn't change with testing conditions c. The main difference between high cycle fatigue and low cycle fatigue is the difference in the number of cycles to failure d. A negative R value in fatigue test indicate the minimum stress is compressive in natureSelect three: Three commonly used tests to measure the hardness related properties of materials are: Rebound Fracture Indentation Scratch Charpy Yield
- What are three commonly used test to measure the hardness related properties of materials?(one or more option can be true please select from below) which of the following will reduce the failure strength or lifetime of a test piece and why? Decreasing the grain size, more grain boundaries to initiate failure Raising the temperature above the BDTT, more plastic deformation in the lattice will cause it to fail faster Increasing its volume, greater likelihood of critical defects Decreasing the loading frequency, the material will be at peak stress values for longer Increasing the difference between the maximum and minimum stress values, as this affects the stress concentration factorThe figure shows two work pieces of steel of 0.3 %C and 1.3 %C with different dimensions. compare between them regarding the diagram that shows the stages of treatments. If we want to treat the samples as follows: - - 1- Sample No.1 with softening annealing treatment. 2- Sample No.2 with normalizing treatment. Subject: Metallurgy
- One metal sample is hot worked 40%; a second sample is hot worked 50%; a third sample is cold worked 40%; a fourth sample is cold worked 50%. Select all of the following that are true. Group of answer choices The 40% hot worked sample would have the highest tensile modulus. The two cold worked samples would have the highest tensile modulus and the cold worked moduli are equal. The 50% cold worked sample would have the highest tensile modulus. The 50% hot worked sample would have the highest tensile modulus. The 40% cold worked sample would have the highest tensile modulus. The two hot worked samples would have the highest tensile modulus and the hot worked moduli are equal. The tensile modulus of all the samples would be about the same.Nondestructive evaluation: Nondestructive evaluation (NDE) describes methodsthat quantitatively characterize materials, tissues, and structures by noninvasivemeans such as X-ray computed tomography, ultrasonics, and acoustic emission.Recently, NDE was used to detect defects in steel castings. (JOM, May 2005.)Assume that the probability that NDE detects a “hit” (i.e., predicts a defect in a steelcasting) when, in fact, a defect exists is .97. (This is often called the probability ofdetection.) Also assume that the probability that NDE detects a “hit” when, in fact,no defect exists is .005. (This is called the probability of a false call.) Past experiencehas shown that a defect occurs once in every 100 steel castings. If NDE detects a“hit” for a particular steel casting, what is the probability that an actual defectexists? Step by Step Full procedure required.Check the incorrect statements. a) As the thickness of the specimen increases, the fracture toughness decreases. b) Hardening a material results in an increase in fracture toughness. c) Larger defects reduce the allowable stress on a mechanical component. d) Increasing temperature usually decreases fracture toughness. e) Eliminating impurities in molten metal and special powder metallurgy techniques that favor the densification of ceramics and metal alloys impair fracture toughness.
- What information does a hardness test reveal?Pick the best soultion for the multiple choices. Modulus of resilience is: Slope of elastic portion of stress – strain curve Area under the elastic portion of the stress –strain curve Energy absorbed during fracture in a tension test Energy absorbed during fracture in an impact test Slope of the plastic portion of the stress- strain curve ( ) Fatigue failure occurs under the condition of: High elastic stress High corrosivity High stress fluctuations High temperature High rate of loading ( ) Creep failure of a material occurs most rapidly when the operating temperature is: Cryogenic temperature Equal to its melting point Grater than 0.4 times its melting point in K Greater than 200 oF Close to boiling point ( ) Young’s modulus of a material is indicative of its: Tensile strength Yield Strength Ductility Stiffness Corrosion Resistance…Provide correct explanation