6. -300 m- 45% 61 m A projectile is launched at 0 with the velocity v at the angle to the horizontal. The parametric equations of the trajectory are x = (v cos 0)t y = −gt² + (v sin 0)t = where t is the time measured from the instant of launch, and g gravitational acceleration. If the projectile is to hit the target A at the 45 determine v, 0, and the time of flight. 9.81 m/s² represents the angle shown in the figure,

Physics for Scientists and Engineers, Technology Update (No access codes included)
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ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter4: Motion In Two Dimensions
Section: Chapter Questions
Problem 4.65AP: A catapult launches a rocket at an angle of 53.0 above the horizontal with an initial speed of 100...
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This subject is on Numerical Methods and Analysis. Write your complete solution to the given problem below.

6.
-300 m-
45%
y = -
61 m
A projectile is launched at 0 with the velocity v at the angle 0 to the horizontal. The
parametric equations of the trajectory are
x = (v cos 0)t
2
gt² + (v sin 0)t
=
where t is the time measured from the instant of launch, and g
gravitational acceleration. If the projectile is to hit the target A at the 45
determine v, 0, and the time of flight.
9.81 m/s represents the
angle shown in the figure,
Transcribed Image Text:6. -300 m- 45% y = - 61 m A projectile is launched at 0 with the velocity v at the angle 0 to the horizontal. The parametric equations of the trajectory are x = (v cos 0)t 2 gt² + (v sin 0)t = where t is the time measured from the instant of launch, and g gravitational acceleration. If the projectile is to hit the target A at the 45 determine v, 0, and the time of flight. 9.81 m/s represents the angle shown in the figure,
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