6. a) Determine Ke at 298 K for the reaction ½ N2(g) + ½ O2(g) + ½ Cl2(g) → NOCI(g), given the following data set at 298 K. ½ N2(g) + O2(g) → NO2(g) Kp = 1.0×10-9 (1) %3D NOCI(g) + ½ O2(g) → NO2C1(g) Kp = 1.1×102 (2) %3D NO2(g) + ½ Cl2(g) → NO2C1(g) Kp = 0.3 (3)
6. a) Determine Ke at 298 K for the reaction ½ N2(g) + ½ O2(g) + ½ Cl2(g) → NOCI(g), given the following data set at 298 K. ½ N2(g) + O2(g) → NO2(g) Kp = 1.0×10-9 (1) %3D NOCI(g) + ½ O2(g) → NO2C1(g) Kp = 1.1×102 (2) %3D NO2(g) + ½ Cl2(g) → NO2C1(g) Kp = 0.3 (3)
Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.56PAE: Describe why it is easier to use Gto determine the spontaneity of a process rather than S u
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Transcribed Image Text:6. a) Determine Ke at 298 K for the reaction ½ N2(g) + ½ O2(g) + ½ Cl2(g) → NOCI(g), given
the following data set at 298 K.
½ N2(g) + O2(g) → NO2(g) Kp = 1.0×10-9
(1)
%3D
NOCI(g) + ½ O2(g) → NO2C1(g) Kp = 1.1×102
(2)
%3D
NO2(g) + ½ Cl2(g) → NO2C1(g) Kp = 0.3
(3)
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