6.) Calculate the molality of the solution (m) Use the equation: Tf (solution) – Tf (solvent) = –i Kf m The freezing point of pure water is 0.00 °C Kf for water is 1.86 °C/m

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6.) Calculate the molality of the solution (m)

Use the equation:

Tf (solution) – Tf (solvent) = –i Kf m

The freezing point of pure water is 0.00 °C

Kf for water is 1.86 °C/m

5.8871
Mass Nacl (g)
100.0
2.
Volume of water (mL)
51.5023
3.
Mass ice (g)
-2.85
Freezing point of the
4.
solution ('C)
Part 1 Calculations
What is the predicted value of i for NaCi?
For electrolytes, assume i = the number of
ions per formula unit.
//
Calculate the molality of the solution (m)
Use the equation:
6.
T; (solution) - T; (solvent) = -i K, m
The freezing point of pure water is 0.00 C
K, for water is 1.86 "C/m
//
Mass of solvent in grams
Add together the masses of the liquid water
and ice added to the calorimeter. Convert
the volume of liquid water to mass using
1.000 g/ml as the density of water (see
procedure for volume used).
Transcribed Image Text:5.8871 Mass Nacl (g) 100.0 2. Volume of water (mL) 51.5023 3. Mass ice (g) -2.85 Freezing point of the 4. solution ('C) Part 1 Calculations What is the predicted value of i for NaCi? For electrolytes, assume i = the number of ions per formula unit. // Calculate the molality of the solution (m) Use the equation: 6. T; (solution) - T; (solvent) = -i K, m The freezing point of pure water is 0.00 C K, for water is 1.86 "C/m // Mass of solvent in grams Add together the masses of the liquid water and ice added to the calorimeter. Convert the volume of liquid water to mass using 1.000 g/ml as the density of water (see procedure for volume used).
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