6. Compute the maximum shear stress and the statical moment for a steel rod with a diameter of 10 in, with a maximum moment of 520 lb ft and a maximum shear of 12 kips (see image below to see information regarding centroids). Data: D = 10 in M = 520 lb-ft V = 12 kips Solution: | = π = Dª 64 Ap = 9= =490.87 in* π-D² 4 2D 3m Q=A, 9= 83.33 in V.Q Tmax = 39.27 in² = 2.12 in =203.72 psi Circular Ap. 2D y= 3m

Mechanics of Materials (MindTap Course List)
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Author:Barry J. Goodno, James M. Gere
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Chapter3: Torsion
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6. Compute the maximum shear stress and the statical moment for a steel rod with a diameter of 10 in, with a
maximum moment of 520 lb ft and a maximum shear of 12 kips (see image below to see information
regarding centroids).
Data:
D = 10 in
M = 520 lb-ft
V = 12 kips
Solution:
1=
Ap
πT Dª
=
64
1
= 490.87 in¹
· (H-DP-²) =
Tmax=
2D
y === 2.12 in
3m
Q=A, y = 83.33 in³
= 39.27 in²
V.Q
1 t
= 203.72 psi
Circular
Ap.
y=
2D
3m
Transcribed Image Text:6. Compute the maximum shear stress and the statical moment for a steel rod with a diameter of 10 in, with a maximum moment of 520 lb ft and a maximum shear of 12 kips (see image below to see information regarding centroids). Data: D = 10 in M = 520 lb-ft V = 12 kips Solution: 1= Ap πT Dª = 64 1 = 490.87 in¹ · (H-DP-²) = Tmax= 2D y === 2.12 in 3m Q=A, y = 83.33 in³ = 39.27 in² V.Q 1 t = 203.72 psi Circular Ap. y= 2D 3m
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