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6. If z = x + iy = (x, y), then the equation z²+z+ 1 = 0 is written as (x,y)(x, y) + (x, y) + (1,0) = (0,0) Which of the following is correct? A. (x² - y² + x + 1, 2xy + y) = (0,0) B. (x² - y² + 2x + 1, 2xy + y) = (0,0) C. (x² + y² + x + 1, 2xy + y) = (0,0) D. (x² - y² + x + 1.4xv + v) = (0,0)

6. If z = x + iy = (x, y), then the equation z²+z+ 1 = 0 is written as (x,y)(x, y) + (x, y) + (1,0) = (0,0) Which of the following is correct? A. (x² - y² + x + 1, 2xy + y) = (0,0) B. (x² - y² + 2x + 1, 2xy + y) = (0,0) C. (x² + y² + x + 1, 2xy + y) = (0,0) D. (x² - y² + x + 1.4xv + v) = (0,0)

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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Please answer problem 6.. thanks
7. The solution z = (x, y) to the equation in Problem 6 is (1/3.+12) 1 3 √√3 B. · (-²2₁ +2²³) D. (-1/²³₁ + ² ) 2 E. none of the above A. 1 √3 2 C.
Transcribed Image Text:7. The solution z = (x, y) to the equation in Problem 6 is (1/3.+12) 1 3 √√3 B. · (-²2₁ +2²³) D. (-1/²³₁ + ² ) 2 E. none of the above A. 1 √3 2 C.
6. If z = x + iy = (x, y), then the equation z²+z+1=0 is written as (x, y)(x, y) + (x, y) + (1,0) = (0,0) Which of the following is correct? A. (x² - y² + x + 1, 2xy + y) = (0,0) B. (x² - y² + 2x + 1, 2xy + y) = (0,0) C. (x² + y² + x + 1, 2xy + y) = (0,0) D. (x² - y² + x + 1,4xy + y) = (0,0) E. None of the above
Transcribed Image Text:6. If z = x + iy = (x, y), then the equation z²+z+1=0 is written as (x, y)(x, y) + (x, y) + (1,0) = (0,0) Which of the following is correct? A. (x² - y² + x + 1, 2xy + y) = (0,0) B. (x² - y² + 2x + 1, 2xy + y) = (0,0) C. (x² + y² + x + 1, 2xy + y) = (0,0) D. (x² - y² + x + 1,4xy + y) = (0,0) E. None of the above
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