6. Let {Xn, n N} be a sequence of independent random variables exponentially distributed with param- eter λ=1. The law of large numbers (LLN) states that: AP(Xi − 2 > e) → 0 for any e > 0 as n → ∞. - X₁ [B]P(|¹ − | > e) → 0 for any € > 0 as n → ∞. C (-2)) → Z, in distribution as n → ∞, where Z is a standard normal. D (²1(x-¹)) → Z, in distribution as n→ ∞o, where Z is a standard normal.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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6. Let {Xn, n € N} be a sequence of independent random variables exponentially distributed with param-
eter λ = 1. The law of large numbers (LLN) states that:
[A]P(2X. - 2 > €) → 0 for any e > 0 as n →∞.
[B]P(EX - }| > )
→ 0 for any € >0 as n → ∞.
[C] (Σ,(X-2)
(1-2)) → Z, in distribution as n → ∞o, where Z is a standard normal.
√4n
[D] (²²–1(X₁-³)) → Z, in distribution as n → ∞, where Z is a standard normal.
Transcribed Image Text:6. Let {Xn, n € N} be a sequence of independent random variables exponentially distributed with param- eter λ = 1. The law of large numbers (LLN) states that: [A]P(2X. - 2 > €) → 0 for any e > 0 as n →∞. [B]P(EX - }| > ) → 0 for any € >0 as n → ∞. [C] (Σ,(X-2) (1-2)) → Z, in distribution as n → ∞o, where Z is a standard normal. √4n [D] (²²–1(X₁-³)) → Z, in distribution as n → ∞, where Z is a standard normal.
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