Using the Atoms, Oxygen, Hydrogen, and Electron (AOHE) method please help me balance the oxidation/reduction reactions I provided an example below on how to solve it using this method thank you so much!Directions: Predict the products and write balanced net ionic equations for the folllowing reactions 6. Predict the products and write balanced net ionic equations for the following reactions.(s) SnCl; is added to KMNO4 solution (acidic) forming Mn". (b) H2S to SO,2 (acidic)Atoms:H2S -> SO,2-4H20 + H2S -> SO42-Охудen:Hydrogen: 4H20 + H2S -> SO4- + 10H*Electrons:4H20 + H2S -> SO4- + 10H* + 8eOxidationWas this half reaction oxidation or reduction?

When KMnO4 (aq) is mixed with a solution of SnCl2(aq) in an acidic solution, the resulting products…

Answered: 6. Predict the products and write…

6. Predict the products and write balanced net ionic equations for the following reactions. (g) SnClz is added to KMNO4 solution (acidic) forming Mn²".

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter23: Voltammetry

Section: Chapter Questions

Problem 23.9QAP

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Concept explainers

Redox Reactions

Redox reactions are considered to be the chemical reactions involving both oxidation and reduction processes. They are actually oxidation-reduction reactions. The term redox is made from two words where “red” comes from reduction and “ox” comes from oxidation. During a redox reaction electron transfer takes place in such a way that one chemical compound gets reduced and the other one gets oxidized.

Question

Using the Atoms, Oxygen, Hydrogen, and Electron (AOHE) method please help me balance the oxidation/reduction reactions I provided an example below on how to solve it using this method thank you so much!

Directions: Predict the products and write balanced net ionic equations for the folllowing reactions

6. Predict the products and write balanced net ionic equations for the following reactions.
(s) SnCl; is added to KMNO4 solution (acidic) forming Mn".

(b) H2S to SO,2 (acidic)
Atoms:
H2S -> SO,2-
4H20 + H2S -> SO42-
Охудen:
Hydrogen: 4H20 + H2S -> SO4- + 10H*
Electrons:
4H20 + H2S -> SO4- + 10H* + 8e
Oxidation
Was this half reaction oxidation or reduction?

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