6. Write a swap function, that swaps the values of two variables in main, but use pointers instead of reference parameters. 7. Write a function that takes an array of ints and its size as arguments. It should create a new array that is the same size as the argument. It should set the values in the new array by adding 10 to each element in the original array. The function should return a pointer to the new array. (Make sure you use dynamic memory allocation) can i get answers for this two sub parts. thanks

6. Write a swap function, that swaps the values of two variables in main, but use pointers instead of reference parameters. 7. Write a function that takes an array of ints and its size as arguments. It should create a new array that is the same size as the argument. It should set the values in the new array by adding 10 to each element in the original array. The function should return a pointer to the new array. (Make sure you use dynamic memory allocation) can i get answers for this two sub parts. thanks

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter7: Arrays

Section7.4: Arrays As Arguments

Problem 5E

See similar textbooks

Similar questions

I need help in this question Given the code segment below, what should be the data type of a in the function prototype of func(), given the call from main()? Do NOT use array indexing notation. If it is an invalid access, write INVALID (in all capital letters) as your answer. void func( ______ a); Int main() { double aData[15]; func(aData[4]); return 0; }
Please write C++ functions, class and methods to answer the following question. Write a function named “removeThisWord” that accepts the vector of pointers toWord objects and a search word. It will go through that list and remove all Wordobjects with the same search word from the vector object. It will return how manyWord objects have been removed.
Suppose that an array is passed as a parameter. How does this differ from the usual use of a value parameter? When an array is passed as a parameter, it is like passed by reference. A new array will be created in the called function and any changes to the new array will pass back to the original array. When an array is passed as a parameter, it is passed by value. So any changes to the parameter do not affect the actual argument. When an array is passed as a parameter, changes to the array affect the actual argument. This is because the parameter is treated as a pointer that points to the first component of the array. This is different from a value parameter (where changes to the parameter do not affect the actual argument). When an array is passed as a value, changes to the array affect the actual argument. This is because the parameter is treated as a pointer that points to the first component of the array. This is different from a parameter (where changes to the parameter do not…
Is that right?For functions that are flexibly bound, you need pointers or references.
Write a function which takes two arguments: a) A NULL-terminated array of pointer to function, and b) a char *. Each function in the array of function parameter takes the string as its argument and returns a string. The returned strings from the function calls should be copied (create a copy of the string) into an array of pointer to char (NULL terminated!) which YOUR function returns. Make the returned array of pointer EXACTLY the right size (count first, then allocate). Use indices to traverse the array of function pointers and the constructed array of pointers to char.
Write three functions for: mean, remove, display //include any standard libraries needed // - passes in an array along with the size of the array // - returns the mean of all values stored in the array double mean( const double array [ ], int arraySize); // - Passes in an array, the size of the array by reference, and the index of a value to be removed from the array. // - Removes the value at this index by shifting all of the values after this value up, keeping the same relative order of all values not removed. // - Refuces arraySize by 1. void remove (double array[], not &arraySize, int index); // - Passes in an array and the size of the array. // - outputs each value in the array separated by a comma and space, with mo comma, space or beeline at the end. void display (const double array[], int arraySize); const int ARR_CAP = 100; int main (int argc, char *argv[]){// verify file name provided on command line // open file and verify it opened // declare an array of doubles of…
I need the answer quickly What is the meaning of the following declaration? int(*p[5])(); a) p is pointer to functionb) p is array of pointer to functionc) p is pointer to such function which return type is the arrayd) p is pointer to array of function
1. Inspect the code and in your own interpretation, describe the reason call to functionChangeIt_1(n) will not change x in main()? 2. Inspect the code and in your own interpretation, describe the reason parameter n inChangeIt_2(int *n) is a pointer, and statement in the function is *n = 6 ? 3. Write a function called void swap with two parameters, which will receive the addressof x and y as pointer. The function should swap the value of x and y only if x is larger thany. Print the value of x and y after the function call. 4. Write a function called double getAverage(int *array, int SIZE), whereit accept the array as pointer, and return the average of the array. Print the returnedvalue from this function. Always use *array rather than subscript to access the arrayvalue.
How come we can pass an array name as an argument to a function and still be able to persist the change? in C++
Write a template function that returns the third minimum out of all the element of an array.The arguments to the function should be the array name and the size of the array (typeint). In main(), exercise the function with arrays of type int, long, double, and char.
Do void and NULL pointers differ? Support your answer with examples. Tabulate the differences.
Inspect the code and in your own interpretation, describe the reason call to function ChangeIt_1(n) will not change x in main()? Inspect the code and in your own interpretation, describe the reason parameter n in ChangeIt_2(int *n) is a pointer, and statement in the function is *n = 6 ? Write a function called void swap with two parameters, which will receive the address of x and y as pointer. The function should swap the value of x and y only if x is larger than y. Print the value of x and y after the function call. Write a function called double getAverage(int *array, int SIZE), where it accept the array as pointer, and return the average of the array. Print the returned value from this function. Always use *array rather than subscript to access the array value.