6.1010 kNA6.112m3 kN/m+2m115 KN+3 mFigure 6.3920 KND4 kN/m3 m5 KN77777771 m[R = 44,875 kN, R. 29,125 KN: V28,87 kN, B,M= 49,375 kN.m, D: PCF 1,211 m from F and 2,947 m from A]

Name: 6.1010 kNA6.112m3 kN/m+2m115 KN+3 mFigure 6.3920 KND4 kN/m3 m5 KN7777
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Description: 6.1010 kNA6.112m3 kN/m+2m115 KN+3 mFigure 6.3920 KND4 kN/m3 m5 KN77777771 m[R = 44,875 kN, R. 29,125 KN: V28,87 kN, B,M= 49,375 kN.m, D: PCF 1,211 m from F and 2,947 m from A]

Find the support reactions, maximum shear force and bending moment, location of point of…

Engineering

Mechanical Engineering

6.10 10 KN 6.11 2m 3 kN/m An + 2m 115 KN C + 3 m Figure 6.39 20 kN D 4 kN/m 3 m 5 KN Thin 1 m +1 [R₁ = 44,875 kN, R. = 29,125 KN; V. -28,87 kN, B; M. 49,375 kN.m, D: PCF 1.211 m from F and 2.947 m from A]

6.10 10 KN 6.11 2m 3 kN/m An + 2m 115 KN C + 3 m Figure 6.39 20 kN D 4 kN/m 3 m 5 KN Thin 1 m +1 [R₁ = 44,875 kN, R. = 29,125 KN; V. -28,87 kN, B; M. 49,375 kN.m, D: PCF 1.211 m from F and 2.947 m from A]

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.3.2P: Repeat the preceding problem using sx= 5.5 MPa. ??y= 4 MPa. and txy= 3.2 MPa.

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