7) In cats, the gene for coat color is both X-linked and incompletely dominant. There are black coat and yellow coat alleles, with calico (tortoise shell) as the heterozygous form. If a yellow male mates with a calico female, what are the expected offspring phenotypes (in percent)?
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Q: The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red…
A: To calculate The map distance separating two genes
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- Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele?Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
- 1. In guinea pigs, black hair (B) is dominant to brown hair (b) and short hair (H) is dominant to long hair (h). A heterozygous black, long-haired guinea pig is crossed with a brown, heterozygous short-haired guinea pig. What percentage of the offspring will be black with long hair?Red-green colorblindness is determined in humans by a single X-linked locus. Colorblind males are XbY, and males with normal vision are XBY. XB is dominant, so XBXB and XBXb females have normal vision, while XbXb females are colorblind. Typically, 8% of males are red-green colorblind. Assuming H-W equilibrium, what percentage of females is typically colorblind?7. In guinea pigs, black hair colour (B) is dominant and brown hair colour (b) is recessive. Long hair (L) is dominant and short hair (l) is recessive. Answer the following questions: (a) Diagram the cross: BbLl x BbLL (b) What are the phenotypes of the parent generation? (c) What are the genotypes and phenotypes of the F1 generation?
- 13. A dominant x-linked allele (B) gives normal color vision but the recessive allele (b) causes red-green color blindness.A. What is the genotype of a man with normal color vision whose father was color- blind? B. What is the genotype of a woman with normal color vision whose father was color-blind? C. If a woman who is colorblind marries a man with normal vision, what would you expect for the genotypes and phenotypes of their children? D. If a man is color-blind, which parent did he inherit the gene from? Explain your answer. E. Which parent does a man get all his x-linked genes from? F. If a woman is color-blind, what do you know about the genotypes and phenotypes of her parents? G. Are men more likely than women to get a genetic disease which is x-linked and dominant? Are they more likely to get a disease that is x-linked and recessive? Explain your answers. H. Can a man with normal color vision have a colorblind daughter? Explain your answer.…1. A pure bred female fruit fly with red eyes and normal bristles is crossed to a pure bred male fruit fly with white eyes and forked bristles. The resulting progeny consist of red eyed males with normal bristles and white females with regular bristles. Determine the mode of inheritance of each trait. Provide the genotypes for parental files and both sexes of the progeny with clearly defined allele designations.Color blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?
- Rabbits can have spotted or solid coats, and the base color can be either black or brown. A spotted coat (P) is dominant over solid (p), and black (B) base color is dominant over brown (b). **None of these traits are sex-linked -they are both autosomal, thus genders are irrelevant. 1. (a) Rabbit 1 is spotted brown: what is its genotype, if its mother was solid black? (b) What are the possible haploid gametes (egg/sperm cells) that would be produced by Rabbit 1? (use F O.I.L.)In humans, being right handed (R) is dominant over being left handed (r), and normal vision (X+) is dominant over color blindness (Xc). Color blindness is a X-linked (a.k.a sex linked) trait. Two right-handed parents with normal vision have a son who is color blind and left handed. What are the genotypes of the parents for right-handedness and color blindness?4. An albino corn snake is crossed with a normal-coloredcorn snake. The offspring are all normal-colored.When these first-generation progeny snakes arecrossed among themselves, they produce 32 normalcolored snakes and 10 albino snakes.a. How do you know that only a single gene is responsible for the color differences between these snakes?
