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- Insurance companies can lower their risks by A) using the law of large numbers to make the number of claims more predictable. B) diversifying across insurance products. C) granting large numbers of independent risk policies. D) all of the above84) plz help exhibit 10.16 is added in the pic Large-scale integrated (LSI) circuit chips are made in one department of an electronics firm. These chips are incorporated into analog devices that are then encased in epoxy. The yield is not particularly good for LSI manufacture, so the AQL specified by that department is 12% while the LTPD acceptable by the assembly department is 35%. Assume the company is willing to accept a consumer's risk of 10 percent and a producer's risk of 5 percent. a. Find the sample size. Use Exhibit 10.16; Note: If the exact value of the computed LTPD/AOQ ratio does not appear in Exhibit 10.16, use the next higher ratio. Note: Round up your answer to the next whole number. b. How would you tell someone to do the test? Randomly sample LSI using the sample size from part a, blank the lot if more than blank defective.lineer sistemin varsa çözümünü bulunuz. (Gauss Metodunu uygulayınız.)
- the question below does not provide sufficient info, i could not apply the vt dt antiderivative formula. I do not know what to do. Dr. James is leaving London for a much needed winter vacation!Unfortunately, his car has been broken for several months, so his speedometer(which measures velocity) and clock (which measures time) both work, but hisodometer (which measures distance travelled) does not.He starts his drive out of the city, but finds himself stuck in traffic. Being bored,and also being a mathematician, he starts to notice that his car’s velocity isa function of the time in hours he has spent on the road. Specifically, after thours, his velocity (according to his speedometer) isv(t) = 8t**2If it takes him 3 hours to get onto the highway out of London, determine thetotal distance he has travelled in those 3 hours.[HINT: You may wish to recall that velocity is the derivative of distance as afunction of time. Reverse this relationship to get yourself started!]6 A valve manufacturer produces a butterfly valve composed of two semicircular plates on acommon spindle that is used to permit flow in one direction only (seen here:http://en.wikipedia.org/wiki/Butterfly_valve). The semicircular plates are supplied by a vendorwith specifications that the plates be 2.37 millimeters thick and have a tensile strength of fivepounds per millimeter. A random sample of 20 such plates is taken. Electronic calipers are usedto measure the thickness of each plate. A universal testing machine was used to test the tensilestrength. The sample data are found in homework 5.xlsx.a. Find point estimates of the thickness and tensile strength data. Compare with thespecifications.b. Construct a 95% confidence interval for mean thickness. Draw conclusions regarding thespecification relative to the confidence interval.c. Construct a 95% confidence interval for mean tensile strength. Draw conclusionsregarding the specification relative to the confidence interval.d. Construct…Child-Proof Bottles. Designing medication packaging that resists opening by children, but yields readily to adults, presents numerous challenges. In the article “Painful Design” (American Scientist, Vol. 93, No. 2, pp. 113–118), H. Petroski examined the packaging used for Aleve, a brand of pain reliever. Three new container designs were given to a panel of children aged 42 months to 51 months. For each design, the children were handed the bottle, shown how to open it, and then left alone with it. If more than 20% of the children succeeded in opening the bottle on their own within 10 minutes, even if by using their teeth, the bottle failed to qualify as child resistant. Identify the a. experimental units. b. response variable. c. factor(s). d. levels of each factor. e. treatments.
- b) Explain the meaning of each term in your own words. a. rejection region b. non rejection region c. critical value(s)Low Carbohydrate Low Fat Mediterranean TOTAL n % n % n % N % Gender 26 26 26 78 Female 15 57.7 15 57.7 14 53.8 44 56.44 Male 11 42.3 11 42.3 12 46.2 34 43.6 Age Group 18-34 years 7 27.9 7 26.9 6 23.1 20 25.6 35-40 years 13 50 14 15.4 15 57.7 42 53.8 50+ years 6 23.1 5 19.2 5 19.2 16 20.5 BMI Category Normal weight 9 34.6 6 23.1 7 26.9 22 28.2 Overweight 11 42.3 13 50 12 46.2 36 46.2 Obese 6 23.1 7 26.9 7 26.9 20 25.6 Write a narrative summary of these findings. Be sure to include a description of the total sample as well as a description of each intervention group.Low Carbohydrate Low Fat Mediterranean TOTAL n % n % n % N % Gender 26 26 26 78 Female 15 57.7 15 57.7 14 53.8 44 56.44 Male 11 42.3 11 42.3 12 46.2 34 43.6 Age Group 18-34 years 7 27.9 7 26.9 6 23.1 20 25.6 35-40 years 13 50 14 15.4 15 57.7 42 53.8 50+ years 6 23.1 5 19.2 5 19.2 16 20.5 BMI Category Normal weight 9 34.6 6 23.1 7 26.9 22 28.2 Overweight 11 42.3 13 50 12 46.2 36 46.2 Obese 6 23.1 7 26.9 7 26.9 20 25.6 Low Carbohydrate Low Fat Mediterranean TOTAL Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Age 39.58 (10.257) (35.54, 43.29) 39.27 (9.594) (35.58, 42.54) 39.69 (10.403) (35.88, 43.65) 39.51 (9.961) (37.17,…
- Low Carbohydrate Low Fat Mediterranean TOTAL n % n % n % N % Gender 26 26 26 78 Female 15 57.7 15 57.7 14 53.8 44 56.44 Male 11 42.3 11 42.3 12 46.2 34 43.6 Age Group 18-34 years 7 27.9 7 26.9 6 23.1 20 25.6 35-40 years 13 50 14 15.4 15 57.7 42 53.8 50+ years 6 23.1 5 19.2 5 19.2 16 20.5 BMI Category Normal weight 9 34.6 6 23.1 7 26.9 22 28.2 Overweight 11 42.3 13 50 12 46.2 36 46.2 Obese 6 23.1 7 26.9 7 26.9 20 25.6 Low Carbohydrate Low Fat Mediterranean TOTAL Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Age 39.58 (10.257) (35.54,43.27) 39.27 (9.594) (35.58,42.54) 39.69 (10.403)…Low Carbohydrate Low Fat Mediterranean TOTAL n % n % n % N % Gender 26 26 26 78 Female 15 57.7 15 57.7 14 53.8 44 56.44 Male 11 42.3 11 42.3 12 46.2 34 43.6 Age Group 18-34 years 7 27.9 7 26.9 6 23.1 20 25.6 35-40 years 13 50 14 15.4 15 57.7 42 53.8 50+ years 6 23.1 5 19.2 5 19.2 16 20.5 BMI Category Normal weight 9 34.6 6 23.1 7 26.9 22 28.2 Overweight 11 42.3 13 50 12 46.2 36 46.2 Obese 6 23.1 7 26.9 7 26.9 20 25.6 Low Carbohydrate Low Fat Mediterranean TOTAL Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Mean (sd) 95% CI (LL,UL) Age 39.58 (10.257) (35.54, 43.29) 39.27 (9.594) (35.58, 42.54) 39.69 (10.403) (35.88, 43.65) 39.51 (9.961) (37.17,…I need help solving this problem and an explanation of how to solve this question Using antiderivatives on a free falling body problem