-7; x<-3 { (x + 2)3 – 6; (x- 2)2 – 5; f (x) = -3 < x < 0 %3D x 2 0 1. lim f(x) = X→-3+ 2. lim f(x) %3D X→-3- 3. lim f(x) = %3D X→-3

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1-3?
-7;
x<-3
f (x) = { (x + 2)³ – 6;
((x- 2)2 – 5;
-3 < x < 0
-
x 2 0
lim f(x) =
%3D
x--3+
2.
lim f(x)
%3D
X→-3-
3.
lim f(x) =
%3D
X→-3
1.
Transcribed Image Text:-7; x<-3 f (x) = { (x + 2)³ – 6; ((x- 2)2 – 5; -3 < x < 0 - x 2 0 lim f(x) = %3D x--3+ 2. lim f(x) %3D X→-3- 3. lim f(x) = %3D X→-3 1.
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