7. A 1650 kg car accelerates up a hill by applying a force of 4.61 x 10³ N parallel to the hill. The hill is at an incline of 13°. m Vo = 16 S d = 17 m 13° a. What is the net work done on the car as it travels 17 m up the hill? (Hint: calculate the work done by each force in the system. There are 3 forces. The net work is the sum of the works done by each individual force.) What is the change in kinetic energy for the car?

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Chapter5: Energy
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Problem 4P: a shopper in a supermarket pushes a cart with a force of 35 N directed at an angle of 25 below the...
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7. A 1650 kg car accelerates up a hill by applying a force of 4.61 × 10³ N parallel to the hill. The hill is at
an incline of 13°.
m
2016
d = 17 m
13°
A.
What is the net work done on the car as it travels 17 m up the hill? (Hint: calculate the work done
by each force in the system. There are 3 forces. The net work is the sum of the works done by
each individual force.)
b. What is the change in kinetic energy for the car?
at the bottom of the hill. How fast is it moving at the top
The car is travelling at a speed of 16
of the hill?
I=
c)
74°F
Transcribed Image Text:7. A 1650 kg car accelerates up a hill by applying a force of 4.61 × 10³ N parallel to the hill. The hill is at an incline of 13°. m 2016 d = 17 m 13° A. What is the net work done on the car as it travels 17 m up the hill? (Hint: calculate the work done by each force in the system. There are 3 forces. The net work is the sum of the works done by each individual force.) b. What is the change in kinetic energy for the car? at the bottom of the hill. How fast is it moving at the top The car is travelling at a speed of 16 of the hill? I= c) 74°F
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